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[英]Why doing Object.create(null) and later setting its prototype to Object.prototype will not allow to execute methods in Object.prototype
[英]Why does setting an object to be not extensible make its [[prototype]] immutable?
MDN - Object.preventExtensions頁面說
該方法使目標的
[[prototype]]
不可變; 任何[[prototype]]
重新分配都會拋出TypeError
。 此行為特定於內部[[prototype]]
屬性,目標 object 的其他屬性將保持可變。
我的問題是:
為什么將 object 設置為不可擴展使其 [[prototype]] 不可變? ( Object.preventExtensions()
, Object.seal()
, Object.freeze()
等)
If the internal [[prototype]]
wasn't made an immutable property, you would be able to circumvent Object.preventExtensions()
by exchanging the internal [[prototype]]
of the object with another value using Object.setPrototypeOf()
, effectively將新值的所有屬性添加到 object:
let a = {}; // a now has all the properties of Array.prototype Object.setPrototypeOf(a, Array.prototype); a.push('foo'); console.log(a); let b = Object.preventExtensions({}); // must not be able add properties to b in the same way Object.setPrototypeOf(b, Array.prototype); b.push('bar'); console.log(b);
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