[英]Making a list from a list of lists, using the same repeated index number for each list created by the enumerate method
我的 function desired_headers() 從“結果” object 中刪除元組,其中元組中的第一個元素與標題列表中的任何字符串都不匹配。 ['Fish', 'Dolphin']
from result1 object & ['Local Auth', 'bucket']
已從 result3 中刪除。
然后它打印索引號和元組列表,如下面的當前 output 所示。
我的目標是使用我當前的 output 將元組列表“重新打包”並存儲在 object 中。
headers2 = ['Group', 'Owner', 'Person in charge', 'Type of Service',
'Registered Care Categories*', 'Specialist Care Categories',
'Languages Spoken by Staff (other than English)','Single Rooms',
'Shared Rooms','Facilities & Service']
result1 = [['Group', 'MacIntyre'], ['Person in charge', ' Vivienne Donald (Manager)'],
['Type of Service', 'good'], ['Fish', 'Dolphin'], ['Shared Rooms', '4']]
result2 = [['Group', 'Jameseson'], ['Type of Service', 'bad'], ['Shared Rooms', '8']]
result3 = [['Group', 'MacIntyre'], ['Person in charge', ' Vivienne Donald (Manager)'],
['Type of Service', 'good'], ['Shared Rooms', '4'], ['Local Auth', 'bucket']]
results = [result1, result2, result3]
#Removes tuples which the first element in the tuple does not matcch any string in headers2 list
def desired_headers():
for index, z in enumerate(list(range(len(results)))):
for i in list(range(len(results[z]))):
if any(x in headers2 for x in results[z][i]):
print(index, results[z][i])
desired_headers()
當前 Output:
0 ['Group', 'MacIntyre']
0 ['Person in charge', ' Vivienne Donald (Manager)']
0 ['Type of Service', 'good']
0 ['Shared Rooms', '4']
1 ['Group', 'Jameseson']
1 ['Type of Service', 'bad']
1 ['Shared Rooms', '8']
2 ['Group', 'MacIntyre']
2 ['Person in charge', ' Vivienne Donald (Manager)']
2 ['Type of Service', 'good']
2 ['Shared Rooms', '4']
所需的 Output:
[[['Group', 'MacIntyre'],
['Person in charge', ' Vivienne Donald (Manager)'],
['Type of Service', 'good'],
['Shared Rooms', '4']],
[['Group', 'Jameseson'], ['Type of Service', 'bad'], ['Shared Rooms', '8']],
[['Group', 'MacIntyre'],
['Person in charge', ' Vivienne Donald (Manager)'],
['Type of Service', 'good'],
['Shared Rooms', '4']]]
你需要這樣的東西嗎? 這會將所有內容分組在一個列表中
# Removes tuples which the first element in the tuple does not matcch any string in headers2 list
def desired_headers():
grouped_elements = []
for index, z in enumerate(list(range(len(results)))):
inner_loop = []
for i in list(range(len(results[z]))):
if any(x in headers2 for x in results[z][i]):
inner_loop.append(results[z][i])
grouped_elements.append(inner_loop)
print(grouped_elements)
嘗試這個
lv1 = [] # initialize an empty list which we will append to based on our criteria
for lst in results: # loop though each element of the list, which itself is a list
lv2 = []
for el in lst: # Same as above
if el[0] in headers2: # check if first element of the list exists in headers2
lv2.append(el)
lv1.append(lv2)
lv1
或者如果你想要一個 function
def desired_headers(list_of_lists, inclution_list):
lv1 = []
for lst in list_of_lists:
lv2 = []
for el in lst:
if el[0] in inclution_list:
lv2.append(el)
lv1.append(lv2)
return lv1
desired_headers(list_of_lists=[result1, result2, result3], inclution_list=headers2)
或者,如果您熟悉列表理解
result = []
for lst in [result1, result2, result3]:
result.append([el for el in lst if el[0] in headers2])
result
您可以通過列表理解來做到這一點:
filtered = [ [sl for sl in r if sl[0] in headers2] for r in results ]
output:
print(filtered)
[
[
['Group', 'MacIntyre'],
['Person in charge', ' Vivienne Donald (Manager)'],
['Type of Service', 'good'],
['Shared Rooms', '4']
],
[
['Group', 'Jameseson'],
['Type of Service', 'bad'],
['Shared Rooms', '8']
],
[
['Group', 'MacIntyre'],
['Person in charge', ' Vivienne Donald (Manager)'],
['Type of Service', 'good'],
['Shared Rooms', '4']
]
]
如果您有大量數據,您可能希望使用headers2
來制作一組用於列表理解
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