Str object 不可調用 TypeError 用於使用 Python 連接四個游戲

Question

我正在通過制作連接四游戲來練習 Python，但我遇到了這個錯誤，我不確定下一步應該采取什么措施來修復它。 文件“main.py”，第 108 行，在 player1() 類型錯誤：'str' object 不可調用

import pandas as pd

data = [[0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 
0, 0], [0, 0, 0, 0 ,0, 0]] 

df = pd.DataFrame(data, columns = ['A', 'B', 'C', 'D', 'E', 'F'])

print(df)

a = df['A']
b = df['B']
c = df['C']
d = df['D']
e = df['E']
f = df['F']

player1 = 'H'
player2 = 'X'

for i in range(len(df)):
  a_cell = a[i]
  b_cell = b[i]
  c_cell = c[i]
  d_cell = d[i]
  e_cell = e[i]
  f_cell = f[i]

  # Prevents board piece from changing after changed once
  if a[i] == 'X' or a[i] == 'H':
    a[i] != player1.inputs or player2.inputs
  if b[i] == 'X' or b[i] == 'H':
    b[i] != player1.inputs or player2.inputs
  if c[i] == 'X' or c[i] == 'H':
    c[i] != player1.inputs or player2.inputs
  if d[i] == 'X' or d[i] == 'H':
    d[i] != player1.inputs or player2.inputs
  if e[i] == 'X' or e[i] == 'H':
    e[i] != player1.inputs or player2.inputs
  if f[i] == 'X' or f[i] == 'H':
    f[i] != player1.inputs or player2.inputs  

# Places board pieces from input
def player1():

  if player1 == "a" and a[i] != "X" and a[i] != "H":
    a[i] = "H"
    print(df)

  elif player1 == "b" and b[i] != 'X' and b[i] != 'H':
    b[i] = "H"
    print(df)

  elif player1 == "c" and c[i] != 'X' and b[i] != 'H':
    c[i] = "H"
    print(df)

  elif player1 == "d" and d[i] != 'X' and b[i] != 'H':
    d[i] = "H"
    print(df)

  elif player1 == "e" and e[i] != 'X' and b[i] != 'H':
    e[i] = "H"
    print(df)

  elif player1 == "f" and f[i] != 'X' and b[i] != 'H':
    f[i] = "H"
    print(df)

  else:
    player1 = input("Player1, select a correct board piece: ")
    player1()

def player2():    

  if player2 == "a" and a[i] != "X" and a[i] != "H":
    a[i] = "X"
    print(df)

  elif player2 == "b" and b[i] != 'X' and b[i] != 'H':
    b[i] = 'X'
    print(df)

  elif player2 == "c" and c[i] != 'X' and c[i] != 'H':
    c[i] = "X"
    print(df)

  elif player2 == "d" and d[i] != 'X' and d[i] != 'H':
    d[i] = "X"
    print(df)

  elif player2 == "e" and e[i] != 'X' and e[i] != 'H' :
    e[i] = "X"
    print(df)

  elif player2 == "f" and f[i] != 'X' and f[i] != 'H':
    f[i] = "X"
    print(df)

  else:
    player2 = input("Player2, select a correct board piece: ")
    player2()

player1 = "H"
player2 = "X"
player1 = input("Player1, select board piece: ")
while True:

  if player1 == 'a' or player1 == 'b' or player1 == 'c' or player1 == 'd' or player1 == 'e' or 
  player1 == 'f':
    player1()
    player2 = input("Player2, select board piece: ")


  elif player2 == 'a' or player2 == 'b' or player2 == 'c' or player2 == 'd' or player2 == 'e' or 
  player2 == 'f':
    player2()
    player1 = input("Player1, select board piece: ")

它還說在分配前引用的第 114 行的 scope 中定義了局部變量“player1”，但在第 109 行有一個用於“player2”的變量

Answer 1

您對 function 和字符串使用相同的名稱。 首先，定義名為player1和player2的函數。 然后，在第 105 行，當您從input捕獲文本時，您將一個字符串分配給變量player1 。 因此，當您嘗試在第 110 行調用player1()時，您會收到錯誤，因為無法調用字符串。

請注意，您還需要為player2修復此錯誤。 您還在 function 定義本身中重復相同的錯誤，在將這些變量定義為字符串之后遞歸調用函數player1和player2 。

Answer 2

問題 1： TypeError

您首先將player1設置為一個字符串，然后定義一個名為player1的 function ，然后再次將player1定義為一個字符串（使用input ），然后嘗試調用player1 （在嘗試調用時是一個字符串）。 嘗試為函數想出不同的名稱，例如move_player1或其他名稱（我將在此答案的第二部分使用此名稱）。

問題 2： UnboundLocalError

至於分配之前引用的變量，您會得到這個，因為當您在player1之外定義move_player1時，如果player1在move_player1中（重新）定義，則 Python 中的范圍規則會創建一個新的player1變量（局部變量）。 因此，您不能引用外部player1並以這種方式重新分配它。 解決此問題的最簡單方法是將player1聲明為全局。

例如：

player1 = "H"

def move_player1():
    global player1
    # ... rest of function

盡管您可能還考慮將player1作為參數傳遞給move_player1並將其定義（使用input ） move_player1之外。