[英]Correcting Pandas Cumulative Sum on a Timedelta Column
我目前有一行代碼用於嘗試創建一個基於日期之間 timedelta 數據累積和的列。 它如何無法在任何地方正確執行累積總和,並且我還收到警告說我的 python 代碼行將來無法正常工作。
原始數據集如下:
ID CREATION_DATE TIMEDIFF EDITNUMB
8211 11/26/2019 13:00 1
8211 1/3/2020 9:11 37 days 20:11:09.000000000 1
8211 2/3/2020 14:52 31 days 05:40:57.000000000 1
8211 3/27/2020 15:00 53 days 00:07:49.000000000 1
8211 4/29/2020 12:07 32 days 21:07:23.000000000 1
這是我的 python 代碼行:
df['RECUR'] = df.groupby(['ID']).TIMEDIFF.apply(lambda x: x.shift().fillna(1).cumsum())
這會產生新列“RECUR”,該列未從“TIMEDIFF”列中的數據正確累計:
ID CREATION_DATE TIMEDIFF EDITNUMB RECUR
8211 11/26/2019 13:00 1 0 days 00:00:01.000000000
8211 1/3/2020 9:11 37 days 20:11:09.000000000 1 0 days 00:00:02.000000000
8211 2/3/2020 14:52 31 days 05:40:57.000000000 1 37 days 20:11:11.000000000
8211 3/27/2020 15:00 53 days 00:07:49.000000000 1 69 days 01:52:08.000000000
8211 4/29/2020 12:07 32 days 21:07:23.000000000 1 122 days 01:59:57.000000000
這也會產生此警告:
FutureWarning: Passing integers to fillna is deprecated, will raise a TypeError in a future version. To retain the old behavior, pass pd.Timedelta(seconds=n) instead.
對此的任何幫助將不勝感激,從 2019 年 11 月 26 日開始,總計應為 153 天,並正確累積顯示在“RECUR”列中。
IIUC,你可以這樣做:
# transform('first') would also work
df['RECUR'] = df['CREATION_DATE'] - df.groupby('ID').CREATION_DATE.transform('min')
Output:
ID CREATION_DATE TIMEDIFF EDITNUMB RECUR
0 8211 2019-11-26 13:00:00 NaT 1 0 days 00:00:00
1 8211 2020-01-03 09:11:00 37 days 20:11:00 1 37 days 20:11:00
2 8211 2020-02-03 14:52:00 31 days 05:41:00 1 69 days 01:52:00
3 8211 2020-03-27 15:00:00 53 days 00:08:00 1 122 days 02:00:00
4 8211 2020-04-29 12:07:00 32 days 21:07:00 1 154 days 23:07:00
您可以使用 0 秒的fillna
timedelta
並執行cumsum
df['RECUR'] = df.groupby('ID').TIMEDIFF.apply(
lambda x: x.fillna(pd.Timedelta(seconds=0)).cumsum())
df['RECUR']
# 0 0 days 00:00:00
# 1 37 days 20:11:09
# 2 69 days 01:52:06
# 3 122 days 01:59:55
# 4 154 days 23:07:18
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