用於在 python 中定義索引和 len() 的循環

Question

任務 1：Python 的len(..) function 接受一個string或一個list ，並返回其長度。 使用len(..) function，對於字符串“Mississippi”中的每個字母，打印“Letter i of Mississippi is:”和字母，其中i是該字母在字符串中的索引。 連接字符串和 integer 時，不要忘記將 integer 轉換為字符串，如表 3 所示。

這是任務，我嘗試了這段代碼，但它只給了我1,2,3,4,5...

我懷疑這是他們想看到的。

>>> city
'Mississippi'
>>> for i in range(len(city)):
    print("Letter i of Mississippi is : " + city[i], str(i))

Answer 1

你快到了

for i in range(len(city)):
    print("Letter {} of Mississippi is : {}".format(i, city[I]))

    print( "Letter " + str(i) + "...")

Answer 2

您應該將i （變量）連接到字符串的中間，代替i （字母）。

for i in range(len(city)):
    print("Letter " + str(i) + " of Mississippi is: " + city[i])

Answer 3

您可以按如下方式打印：

for i in range(len(city)):
    print(f"Letter {i} of Mississippi is : {city[i]}")

Answer 4

解決方案1：

for i in range(len(city)):
    print(f"Letter {city[i]} of Mississippi is at index {str(i)}")

Letter M of Mississippi is at index 0
Letter i of Mississippi is at index 1
Letter s of Mississippi is at index 2
Letter s of Mississippi is at index 3
Letter i of Mississippi is at index 4
Letter s of Mississippi is at index 5
Letter s of Mississippi is at index 6
Letter i of Mississippi is at index 7
Letter p of Mississippi is at index 8
Letter p of Mississippi is at index 9
Letter i of Mississippi is at index 10

使用列表理解的解決方案 2 ：

[f"Letter {city[i]} of Mississippi is at index {str(i)}" for i in range(len(city))]

['Letter M of Mississippi is at index 0',
 'Letter i of Mississippi is at index 1',
 'Letter s of Mississippi is at index 2',
 'Letter s of Mississippi is at index 3',
 'Letter i of Mississippi is at index 4',
 'Letter s of Mississippi is at index 5',
 'Letter s of Mississippi is at index 6',
 'Letter i of Mississippi is at index 7',
 'Letter p of Mississippi is at index 8',
 'Letter p of Mississippi is at index 9',
 'Letter i of Mississippi is at index 10']