[英]Circular Reference in XmlSerializer c#
我正在制作一個應用程序,我可以在其中將信號相互連接。 這將創建一個循環引用。 我看到的示例顯示了父子結構的解決方案。 在我的應用程序中,我將來自同一個 class 的 2 個對象相互連接,因此我不能簡單地忽略其中一個引用。
我做了一個簡單的例子來說明我的應用程序正在做什么:
class Program
{
static void Main(string[] args)
{
Info i = new Info();
Employee bs = new Employee("asfdljfoiej", i);
Employee ss = new Employee("asfdljfj", i);
bs.conEm = ss;
ss.conEm = bs;
XmlSerializer xs = new XmlSerializer(typeof(Employee));
const string path = @"C:\Users\Joris.Bosma.KG\source\repos\TestProject\TestProject\bin\Debug\Serializing.xml";
TextWriter txtWriter = new StreamWriter(path);
xs.Serialize(txtWriter, bs);
txtWriter.Close();
//---------------------------------------------------------------------------------------------------------------------------------------
Program p = new Program();
p.Deserialize("Serializing.xml");
}
public void Deserialize(string filename)
{
XmlSerializer xs2 = new XmlSerializer(typeof(Employee));
Employee em;
using (Stream reader = new FileStream(filename, FileMode.Open))
em = (Employee)xs2.Deserialize(reader);
Console.Write(em.name);
}
}
public class Employee
{
public int Id = 1;
public String name = "John Smith";
public string subject = "Physics";
public string random;
public List<Employee> Employees;
public Employee conEm;
public Info inf;
public Employee()
{
}
public Employee(String s, Info i)
{
random = s;
inf = i;
}
}
public class Info : Employee
{
public string add = "Street";
}
問題出在bs.conEm = ss ss.conEm = bs
感謝您提前提供幫助!
如果員工的結構不是分層結構(可能存在循環),我建議從序列化中排除屬性“conEm”和“Employees”,並將數據存儲在如下結構中:
public class Relationship {
public int ParentId { get; set; }
public int ChildId { get; set; }
}
public class DataStore {
// flat list of employees
public List<Employee> Employees { get; set; }
// list of all relationship between Employees
public List<Relationship> Relationships { get; set; }
}
這個結構需要在序列化之前填充。
反序列化后,結構很容易恢復:
var index = data.Employees.ToLookup(e => e.Id);
data.Relationships.Iter(r => {
var parent = index[r.ParentId].FirstOrDefault();
var child = index[r.ChildId].FirstOrDefault();
if (parent != nuu && child != null) {
parent.Employees.Add(child);
child.conEm = parent;
}
});
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.