我該怎么辦？（類型錯誤）

Question

import re

ffail = ""
with open("regex_sum_340933.txt", "r" , "UTF-8") as some_file:
    ffail = some_file.read()
count = 0

match = re.findall('[0-9]+', ffail)

for II in match:
    number = int(II)
    count = count + number
print(count)

這段代碼給了我這個錯誤： with open("regex_sum_340933.txt", "r", "UTF-8") as some_file: TypeError: an integer is required (got type str)

Answer 1

open的第三個參數是buffering （請參閱文檔），而不是encoding ，因此您需要將encoding作為關鍵字參數傳遞。 另外，最好使用"utf8" 。

with open("regex_sum_340933.txt", "r" , encoding="utf8") as some_file: