What should I do?(TypeError)

Question

import re

ffail = ""
with open("regex_sum_340933.txt", "r" , "UTF-8") as some_file:
    ffail = some_file.read()
count = 0

match = re.findall('[0-9]+', ffail)

for II in match:
    number = int(II)
    count = count + number
print(count)

This code gives me this error: with open("regex_sum_340933.txt", "r", "UTF-8") as some_file: TypeError: an integer is required (got type str)

Answer 1

open 's third argument is buffering ( see the docs ), not encoding , so you need to pass encoding as a keyword argument. Also, it's better to use "utf8" .

with open("regex_sum_340933.txt", "r" , encoding="utf8") as some_file: