[英]C# How to add an element to List<string>?
如何將元素電影添加到現有類別元素? 目前我只能在兩個字段上創建新的列表條目。
class MovieSolver
{
public string Category { get; set; }
public List<string> Movie { get; set; }
}
class CreateMovieList
{
readonly static List<MovieSolver> playerTargetList = new List<MovieSolver>();
public static void MovieCBO()
{
playerTargetList.Add(new MovieSolver { Category = "Action", Movie = new List<string> { "Taken", "The Factory", "Wind River" } });
playerTargetList.Add(new MovieSolver { Category = "Comedy", Movie = new List<string> { "Gold", "Hangover", "We are the Millers" } });
playerTargetList.Add(new MovieSolver { Category = "Thriller", Movie = new List<string> { "Jack Reacher", "Real Steel", "Iron Man I" } });
}
}
除了有更聰明的方法來創建class MovieSolver
嗎?
首先,我在這里根本找不到一個 int 列表。
如果要將新字符串 object 添加到 MoveiSolver object 中的列表,您首先需要找到要添加新字符串元素的 Moviesolver object。
您可以使用 for 循環、foreach 循環或 LINQ 來執行此操作。
對於新程序員來說,foreach 通常是最容易理解的。
Foreach item in playerTargetList
{
if(item.category == "Action")
{
item.Movie.add("lorum ipsum");
}
}
你為什么不在這里使用像Dictionary<string, List<string>>
這樣的默認值 class?
//Add library reference
using System.Collections.Generic;
public void MyMethod()
{
//Initialize a Dictionary
Dictionary<string, List<string>> MovieCBO = new Dictionary<string, List<string>>();
//Check if its an existing category
//If its an existing category, add the movie to existing list
if (MovieCBO.ContainsKey("some_category"))
{
MovieCBO["some_category"].Add("new_movie_name");
}
//If its a new category, add category along the movie
else
{
MovieCBO.Add("some_category", new List<string>() { "new_movie_name" });
}
}
所有操作都將在恆定時間內完成。 這比遍歷列表中的所有項目並檢查類別要快得多。
您可以將方法addMovie添加到 class CreateMovieList以驗證 MovieSolver 是否尚不存在並在必要時創建它
public static void addMovie(String category, String movie)
{
var movieSolver = playerTargetList.Find(e => e.Category == category);
if(movieSolver != null)
{
var existingMovie = movieSolver.Movie.Find( e => e == movie);
if (existingMovie == null)
movieSolver.Movie.Add(movie);
}
else
playerTargetList.Add(new MovieSolver { Category = category, Movie = new List<string> { movie } });
}
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