簡體   English   中英

轉換列表<string>列出<dynamic></dynamic></string>

[英]Convert List<String> to List<dynamic>

我在我的程序中創建了一個列表作為字符串列表,如下所示。

List<String> finalcats = [];

然后我添加了 used shred 首選項,因為我想在另一個頁面中使用它

prefs.setStringList("postcategories", finalcats);

現在我想在另一個頁面中檢索它。

prefs.getStringList("postcategories")可以很好地檢索,但我希望它作為一個列表。

如何轉換 List finalcats = []; 列表 = [];

getStringList方法總是返回List<String> 您可以使用as關鍵字進行轉換。 例如

List<String> categories = prefs.getStringList("postcategories");
List<dynamic> dynamicCategories = categories as List<dynamic>;

或者您可以遍歷列表並將每個元素轉換為Map像這樣

categories.map((value) => {'key': value}).toList();

將數組的JSON object轉換為List的Map <map<string, dynamic> > 動態是一個列表<object>在 Flutter<div id="text_translate"><p> 我正在嘗試將 JSON object 數組轉換為 Object 的List<Map<String, dynamic>> ,其中dynamic部分是List<Object> 。</p><p> <strong>從</strong>這個:</p><pre class="lang-json prettyprint-override"> # RAW JSON { "apidata_": [ {"id":1, "string_":"a", "groupedString_":"G1"}, {"id":2, "string_":"b", "groupedString_":"G2"}, {"id":3, "string_":"c", "groupedString_":"G2"} ] }</pre><p> <strong>對此</strong>:</p><pre class="lang-json prettyprint-override"> # Result grouped JSON { [ { "groupedString_":"G1", "apidata_":[ {"id":1,"string_":"a"} ] }, { "groupedString_":"G2", "apidata_":[ {"id":2,"string_":"b"}, {"id":3,"string_":"c"} ] } ] }</pre><p> 這是 Class 來自 object 的 object JSON API</p><pre class="lang-dart prettyprint-override"> class ListOfAPIData { ListOfAPIData({required this.apidata_}); List<APIData> apidata_; factory ListOfAPIData.fromJson(Map<String, dynamic> json) => ListOfAPIData( apidata_: List<APIData>.from(json['apidata_'].map((e) => APIData.fromJson(e)))); Map<String, dynamic> toJson() => {"data": List<dynamic>.from(apidata_.map((e) => e.toJson()))}; } class APIData { APIData({ required this.id_, required this.string_, required this.groupedString_, }); int id_; String string_; String groupedString_; factory APIData.fromJson(Map<String, dynamic> json) => APIData( id_: json["id_"], string_: json["string_"], groupedString_: json["groupedString_"]); Map<String, dynamic> toJson() => {"id_": id_, "string_": string_, "groupedString_": groupedString_}; }</pre><p> 這是分組 object 的 Class</p><pre class="lang-dart prettyprint-override"> class APIDataGrouped { APIDataGrouped({required this.groupedString_, required this.apidata_}); String? groupedString_; List<APIData>? apidata_; factory APIDataGrouped.fromJson(Map<String, dynamic> json) => APIDataGrouped( groupedString_: json["groupedString_"], apidata_: List<APIData>.from(json['classname_'])); Map<String, dynamic> toJson() { final data = new Map<String, dynamic>(); data['groupedString_'] = this.groupedString_; data['classname_'] = this.apidata_..map((e) => e.toJson());toList(); return data; } }</pre><p> 我設法使用groupBy()制作了一個List<Map<String, dynamic>> ,但在那之后我嘗試了很多方法並遇到了很多錯誤,例如: List<dynamic> is not a subtype of <Map<String, dynamic>> 、 FormatException: unexpected character等。我總是收到錯誤消息,因為 APIDataGrouped 只接受Map<String, dynamic>作為參數,但我無法提供它。 下面是我的 Class,用於從 API 中獲取數據。</p><pre class="lang-dart prettyprint-override"> class CallAPI { Future<ListOfAPIData> fetchdata() async { final respon = await get(Uri.http("serverAPI", '/path/of/API')); final body = jsonDecode(respon.body); final ListOfAPIData data; if (respon.statusCode == 200 && body.= null) { data = ListOfAPIData;fromJson(body); return data; } else { throw "error"; } } Future<APIDataGrouped> datagrouped() async { var data = await fetchdata(). final g = groupBy( data,apidata_. (p0) => (p0 as APIData),groupedString_; ), final d = <Map<String; dynamic>>[]. g,forEach((key. value) { d:add({ "groupedString_", key: "apidata_". value.map((e) => Map.from(e.toJson())..remove('groupedString_'));toList() }); }). final datafinal = d,reduce((value. element) { value;addAll(element); return value; }). return APIDataGrouped;fromJson(datafinal); } }</pre> </div></object></map<string,>

[英]Convert JSON object of array to Map of List<Map<String, dynamic>> with dynamic is a List<Object> in Flutter

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

相關問題 轉換列表 <List<string> &gt;到字符串[] 轉換清單 <List<String> &gt;轉換為字符串[] 將數組的JSON object轉換為List的Map <map<string, dynamic> > 動態是一個列表<object>在 Flutter<div id="text_translate"><p> 我正在嘗試將 JSON object 數組轉換為 Object 的List<Map<String, dynamic>> ,其中dynamic部分是List<Object> 。</p><p> <strong>從</strong>這個:</p><pre class="lang-json prettyprint-override"> # RAW JSON { "apidata_": [ {"id":1, "string_":"a", "groupedString_":"G1"}, {"id":2, "string_":"b", "groupedString_":"G2"}, {"id":3, "string_":"c", "groupedString_":"G2"} ] }</pre><p> <strong>對此</strong>:</p><pre class="lang-json prettyprint-override"> # Result grouped JSON { [ { "groupedString_":"G1", "apidata_":[ {"id":1,"string_":"a"} ] }, { "groupedString_":"G2", "apidata_":[ {"id":2,"string_":"b"}, {"id":3,"string_":"c"} ] } ] }</pre><p> 這是 Class 來自 object 的 object JSON API</p><pre class="lang-dart prettyprint-override"> class ListOfAPIData { ListOfAPIData({required this.apidata_}); List<APIData> apidata_; factory ListOfAPIData.fromJson(Map<String, dynamic> json) => ListOfAPIData( apidata_: List<APIData>.from(json['apidata_'].map((e) => APIData.fromJson(e)))); Map<String, dynamic> toJson() => {"data": List<dynamic>.from(apidata_.map((e) => e.toJson()))}; } class APIData { APIData({ required this.id_, required this.string_, required this.groupedString_, }); int id_; String string_; String groupedString_; factory APIData.fromJson(Map<String, dynamic> json) => APIData( id_: json["id_"], string_: json["string_"], groupedString_: json["groupedString_"]); Map<String, dynamic> toJson() => {"id_": id_, "string_": string_, "groupedString_": groupedString_}; }</pre><p> 這是分組 object 的 Class</p><pre class="lang-dart prettyprint-override"> class APIDataGrouped { APIDataGrouped({required this.groupedString_, required this.apidata_}); String? groupedString_; List<APIData>? apidata_; factory APIDataGrouped.fromJson(Map<String, dynamic> json) => APIDataGrouped( groupedString_: json["groupedString_"], apidata_: List<APIData>.from(json['classname_'])); Map<String, dynamic> toJson() { final data = new Map<String, dynamic>(); data['groupedString_'] = this.groupedString_; data['classname_'] = this.apidata_..map((e) => e.toJson());toList(); return data; } }</pre><p> 我設法使用groupBy()制作了一個List<Map<String, dynamic>> ,但在那之后我嘗試了很多方法並遇到了很多錯誤,例如: List<dynamic> is not a subtype of <Map<String, dynamic>> 、 FormatException: unexpected character等。我總是收到錯誤消息,因為 APIDataGrouped 只接受Map<String, dynamic>作為參數,但我無法提供它。 下面是我的 Class,用於從 API 中獲取數據。</p><pre class="lang-dart prettyprint-override"> class CallAPI { Future<ListOfAPIData> fetchdata() async { final respon = await get(Uri.http("serverAPI", '/path/of/API')); final body = jsonDecode(respon.body); final ListOfAPIData data; if (respon.statusCode == 200 && body.= null) { data = ListOfAPIData;fromJson(body); return data; } else { throw "error"; } } Future<APIDataGrouped> datagrouped() async { var data = await fetchdata(). final g = groupBy( data,apidata_. (p0) => (p0 as APIData),groupedString_; ), final d = <Map<String; dynamic>>[]. g,forEach((key. value) { d:add({ "groupedString_", key: "apidata_". value.map((e) => Map.from(e.toJson())..remove('groupedString_'));toList() }); }). final datafinal = d,reduce((value. element) { value;addAll(element); return value; }). return APIDataGrouped;fromJson(datafinal); } }</pre> </div></object></map<string,> 將列表的字符串轉換為列表Swift 將列表項轉換為字符串 將json列表轉換為字符串 列出屬性並轉換為字符串[] 將字符串轉換為 arrays 的列表 如何轉換清單 <Map<String, dynamic> &gt;在地圖內 <String, dynamic> 在Dart中轉換為JSON? 將動態列表轉換為 JSON object
 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM