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[英]How to convert dataframe column which contains list of dictionary into separate columns?
[英]A dictionary has a separate dictionary and i want to convert it in dataframe in python such that the table contains columns which has sub columns
Data=[{'endDate': {'raw': 1585612800, 'fmt': '2020-03-31'},
'totalRevenue': {'raw': 67985000, 'fmt': '67.98M', 'longFmt':
'67,985,000'},
'costOfRevenue': {'raw': 0, 'fmt': None, 'longFmt': '0'},
'grossProfit': {'raw': 67985000, 'fmt': '67.98M', 'longFmt':
'67,985,000'},
'sellingGeneralAdministrative': {'raw': 37779000,
'fmt': '37.78M'}},
{'endDate': {'raw': 1577750400, 'fmt': '2019-12-31'},
'totalRevenue': {'raw': 79115000, 'fmt': '79.11M', 'longFmt':
'79,115,000'},
'costOfRevenue': {'raw': 0, 'fmt': None, 'longFmt': '0'},
'grossProfit': {'raw': 79115000, 'fmt': '79.11M', 'longFmt':
'79,115,000'},
' sellingGeneralAdministrative': {'raw': 36792000,
'fmt': '36.79M',
'longFmt': '36,792,000'}}]
i want Data in this format
Data =[{endDate:{'fmt':'2020-03-31'},
totalRevenue:{'fmt':67.98M},
costofRevenue:{'fmt':None}' and so on
即刪除'raw'和'longfmt',然后我希望它將dict列表轉換為dataframe。
以下是將多個這樣的字典轉換為 dataframe 的方法:
import pandas as pd
a = {...}
b = {...}
c = [a, b]
f = {'grossProfit':[], 'incomeBeforeTax':[], 'incomeTaxExpense':[]}
for e in c:
for k in f.keys():
f[d].append(e[d])
print(pd.DataFrame(f))
pandas
實際上並不支持“子列”,正如您所要求的那樣。 但是,它確實支持以{'a': {'b': 'value'}}
為您提供列ab = 'value'
的方式展平json
對象。 執行此操作的官方方法是json_normalize
,並且會像這樣使用
import pandas as pd
income_statement_history = {
"totalRevenue": {
"raw": 67985000,
"fmt": "67.98M",
"longFmt": "67,985,000"
},
"costOfRevenue": {
"raw": 0,
"fmt": 'null',
"longFmt": "0"
},
"grossProfit": {
"raw": 67985000,
"fmt": "67.98M",
"longFmt": "67,985,000"
},
"totalOperatingExpenses": {
"raw": 46790000,
"fmt": "46.79M",
"longFmt": "46,790,000"
},
"operatingIncome": {
"raw": 21195000,
"fmt": "21.2M",
"longFmt": "21,195,000"
}
}
df = pd.json_normalize(income_statement_history)
打印df
會給你
>>> df
totalRevenue.raw totalRevenue.fmt totalRevenue.longFmt costOfRevenue.raw costOfRevenue.fmt ... totalOperatingExpenses.fmt totalOperatingExpenses.longFmt operatingIncome.raw operatingIncome.fmt operatingIncome.longFmt
0 67985000 67.98M 67,985,000 0 null ... 46.79M 46,790,000 21195000 21.2M 21,195,000
[1 rows x 15 columns]
您可以繼續動態訪問這些列值
>>> col = 'totalOperatingExpenses'
>>> subcol = 'longFmt'
>>> df[f'{col}.{subcol}']
0 46,790,000
Name: totalOperatingExpenses.longFmt, dtype: object
在這之間做出決定,如@Ann Zen 的回答所建議的pd.DataFrame
初始化,或者您一直使用的任何方法,取決於您的確切需要。
您的目標是基於 json 數據的視覺上令人愉悅的列配置嗎? 給定子列的名稱和基列的名稱,您的目標是訪問子列的清晰方法嗎? 我能想到的大多數答案僅基於偏好,差異很小。
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