如何從 C# 中的 Folder.Zip 創建 Subfolder.Zip 文件

Question

我正在嘗試使用 .NETCore LAMBDA function 從 Build Artifacts 創建一些包，由於存儲限制 LAMBDA 臨時存儲僅為 512，因此面臨一些問題我的工件（Zip 文件大小為 300MB）結構是

./scripts.bat
./scripts2.yml
./Env/Svr1/somefile.txt
./Env/Svr1/somefolder/somefile.txt
./Env/Svr1/somefolder/someotherfolder/somefile.txt

任務是將scripts.bat和scripts2.yml復制到./Env/Svr1/和zip的Svr1（不包括./Env/Svr2/..etc中的其他文件夾）的內容為./Svr1.zip在根級別沒有解壓縮整個 zip，因為存儲是受限的。

                var tempPath = @"/tmp/"; 
                using (var file = File.OpenRead(tempPath+ "MyZipFile.zip"))
                {
                    using (var zipFile = new ZipArchive(file, ZipArchiveMode.Read, true))
                    {
                        var ymlConfigs = zipFile.Entries.Select(f => f.Name).Where(en => en.EndsWith(".yml"));
                        var batFiles = zipFile.Entries.Select(f => f.Name).Where(en => en.EndsWith(".bat"));
                        var svr1Folder = zipFile.Entries.Select(folder => folder.FullName).Where(name => name.StartsWith("Env/Svr1"));                          
                                     
                         //add yml files to package 
                        foreach (var ymlfile in ymlConfigs)
                        {
                            svr1Folder.Concat(new[] { ymlfile });                               
                        }
                        //add bat files to package 
                        foreach (var batfile in batFiles)
                        {
                            svr1Folder.Concat(new[] { batfile });                           
                        }
                          //create zip package 
                        var newZip = ZipFile.Open(tempPath + "Svr1", ZipArchiveMode.Update);
                        foreach (var item in svr1Folder)
                        {
                            newZip.CreateEntryFromFile(item, Path.GetFileName(item), CompressionLevel.Optimal); 
//Error Could not find a part of the path as its looking for Item in Debug folder  ..\bin\Debug\netcoreapp3.1\Env\Svr1\somefile.txt where as my item is in ./tmp/MyZipFile.zip                              
                        }
                    }
                }

Answer 1

我設法找到一個解決方案，將 zip 文件讀取為 Stream 並創建一個新的 zip 文件，其中包含空文件夾並從原始文件中添加所需的條目。

using (FileStream zipToOpen = new FileStream(tempPath + folder + ".zip", 
FileMode.Open))
{
using (ZipArchive archive = new ZipArchive(zipToOpen, 
ZipArchiveMode.Update))
{
  foreach (var item in svr1Package)
  {
   var splitString = item.FullName.Split("/");
   var path = String.Join("/", item.FullName.Split("/").Skip(2));
   if (!String.IsNullOrEmpty(path))
   {
      var temp = path.Substring(0,path.LastIndexOf("/"));
      var outputpath = Path.Combine(tempPath, temp);
      var readEntry = archive.CreateEntry(path);//creates file with this 
                                                //name
     //read data from original item and load in memory 
      var inputStream = item.Open();
      byte[] data = null;
      byte[] buffer = new byte[16 * 1024];
      using (MemoryStream memoryStream = new MemoryStream())
      {
       int read;
       while ((read = inputStream.Read(buffer, 0,buffer.Length)) > 0)
       {
          memoryStream.Write(buffer, 0, read);
       }
       data = memoryStream.ToArray();
       }
       //write back data to newZip file 
       using (BinaryWriter writer = new BinaryWriter(readEntry.Open()))
       {
           writer.Write(data);
       }
     }
       else //these are just txt or bat files copy as it is 
     {
     if ((item.FullName.StartsWith("appspec_sv1")) || 
        (item.FullName.StartsWith("appspec_sv2")))
        {
         var readEntry = archive.CreateEntry("appspec.yml");
         StringBuilder stringBuilder;
         using (StreamReader reader = new StreamReader(item.Open()))
         {
           stringBuilder = new StringBuilder(reader.ReadToEnd());
         }
         using (StreamWriter writer = new StreamWriter(readEntry.Open()))
         {
                                writer.Write(stringBuilder);
         }
     }
          else
          {
           var readEntry = archive.CreateEntry(item.FullName);
           StringBuilder stringBuilder;
           using (StreamReader reader = new StreamReader(item.Open()))
           {
            stringBuilder = new StringBuilder(reader.ReadToEnd());
           }
          using (StreamWriter writer = new StreamWriter(readEntry.Open()))
          {
                 writer.Write(stringBuilder);
          }
    }
  }
}
  transferUtility.Upload(tempPath + folder + ".zip",bucketName, 
  outputPrefix + folder + ".zip");

}

Answer 2

我已經回答了如何在 .NET 中創建 zip 之前的這篇文章在 ZipArchive 中創建目錄 C#.Net 4.5我認為你仍然可以在 dotnet 核心中應用。

此外，如果您在類 unix 環境中運行應用程序，則可以簡單地使用 zip 命令，該命令可能在 AWS 上可用

干杯，香草