使用 dict python 提取坐標值

Question

我真的需要幫助

dict 值的 1 看起來像這樣。 （我突出顯示了 x 和 y 值） ：

 {
    "objects": [
        {
            "featureId": "ckbrnqtf600jb0y6o1hsnanqj",
            "schemaId": "ckbrnnh4b009w0y5h4nend1n3",
            "title": "point",
            "value": "point",
            "color": "#FF0000",
            "point": {"x": 1262, "y": 161},
            "instanceURI": "https://api.labelbox.com/masks/feature/ckbrnqtf600jb0y6o1hsnanqj?token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJ1c2VySWQiOiJja2JyaWh4b3JjYTBjMDc2Mml1OHR6Y3plIiwib3JnYW5pemF0aW9uSWQiOiJja2JyaWh4bnk0cnp1MDc3NjdmbmM1YXV4IiwiaWF0IjoxNTkyOTAzNDk0LCJleHAiOjE1OTU0OTU0OTR9.p1xWGMeXVJysOcYNjQbSHOlpnVdATkMwu-Ze-zm_wlg",
        },
        {
            "featureId": "ckbrnqwdw0fbq0z808cxg5dbl",
            "schemaId": "ckbrnnh4b009w0y5h4nend1n3",
            "title": "point",
            "value": "point",
            "color": "#FF0000",
            "point": {"x": 1320, "y": 162},
            "instanceURI": "https://api.labelbox.com/masks/feature/ckbrnqwdw0fbq0z808cxg5dbl?token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJ1c2VySWQiOiJja2JyaWh4b3JjYTBjMDc2Mml1OHR6Y3plIiwib3JnYW5pemF0aW9uSWQiOiJja2JyaWh4bnk0cnp1MDc3NjdmbmM1YXV4IiwiaWF0IjoxNTkyOTAzNDk0LCJleHAiOjE1OTU0OTU0OTR9.p1xWGMeXVJysOcYNjQbSHOlpnVdATkMwu-Ze-zm_wlg",
        },
        {
            "featureId": "ckbrnqzfp00ji0y6ocz24ajah",
            "schemaId": "ckbrnnh4b009w0y5h4nend1n3",
            "title": "point",
            "value": "point",
            "color": "#FF0000",
            "point": {"x": 1278, "y": 205},
            "instanceURI": "https://api.labelbox.com/masks/feature/ckbrnqzfp00ji0y6ocz24ajah?token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJ1c2VySWQiOiJja2JyaWh4b3JjYTBjMDc2Mml1OHR6Y3plIiwib3JnYW5pemF0aW9uSWQiOiJja2JyaWh4bnk0cnp1MDc3NjdmbmM1YXV4IiwiaWF0IjoxNTkyOTAzNDk0LCJleHAiOjE1OTU0OTU0OTR9.p1xWGMeXVJysOcYNjQbSHOlpnVdATkMwu-Ze-zm_wlg",
        },
        {
            "featureId": "ckbrnr2vx0fos0y84dgi1ck5s",
            "schemaId": "ckbrnnh4b009w0y5h4nend1n3",
            "title": "point",
            "value": "point",
            "color": "#FF0000",
            "point": {"x": 1328, "y": 210},
            "instanceURI": "https://api.labelbox.com/masks/feature/ckbrnr2vx0fos0y84dgi1ck5s?token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJ1c2VySWQiOiJja2JyaWh4b3JjYTBjMDc2Mml1OHR6Y3plIiwib3JnYW5pemF0aW9uSWQiOiJja2JyaWh4bnk0cnp1MDc3NjdmbmM1YXV4IiwiaWF0IjoxNTkyOTAzNDk0LCJleHAiOjE1OTU0OTU0OTR9.p1xWGMeXVJysOcYNjQbSHOlpnVdATkMwu-Ze-zm_wlg",
        },
    ],
    "classifications": [],
}

 import json json1_file = open('/content/export-2020-06-30T12_57_16.744Z.json') json1_str = json1_file.read() json1_data = json.loads(json1_str) json1_data = json.loads(json1_str)[0] print("Type:", type(json1_data))

在代碼中，我將 JSON 轉換為 dict ，現在我必須提取值並將其保存在一行中。 請幫助代碼，我如何提取這些 x 和 y 值。

Answer 1

那不是那么困難。 我以縮短的形式添加了輸入數據：

dict= {"objects":[
{"featureId":"ckbrnqtf600jb0y6o1hsnanqj","schemaId":"ckbrnnh4b009w0y5h4nend1n3","title":"point","value":"point","color":"#FF0000",
    "point":{"x":1262,"y":161},"instanceURI":"https:"},
{"featureId":"ckbrnqwdw0fbq0z808cxg5dbl","schemaId":"ckbrnnh4b009w0y5h4nend1n3","title":"point","value":"point","color":"#FF0000",
    "point":{"x":1320,"y":162},"instanceURI":"https:"},
{"featureId":"ckbrnqzfp00ji0y6ocz24ajah","schemaId":"ckbrnnh4b009w0y5h4nend1n3","title":"point","value":"point","color":"#FF0000",
    "point":{"x":1278,"y":205},"instanceURI":"https:"},
{"featureId":"ckbrnr2vx0fos0y84dgi1ck5s","schemaId":"ckbrnnh4b009w0y5h4nend1n3","title":"point","value":"point","color":"#FF0000",
    "point":{"x":1328,"y":210},"instanceURI":"https:"}],"classifications":[]}

for d in dict["objects"]:
    x = d["point"]["x"]
    y = d["point"]["y"]
    print(x,y)

輸出：

1262 161
1320 162
1278 205
1328 210

作為元組列表：

print([(d["point"]["x"], d["point"]["y"]) for d in dict["objects"]])

輸出：

[(1262, 161), (1320, 162), (1278, 205), (1328, 210)]

json文件中的所有字典：

根據我可以從您發布的代碼中得出的信息，它應該是這樣的：

with open ('/content/export-2020-06-30T12_57_16.744Z.json', 'r') as jsonfile:
    json1_str = jsonfile.read()
json1_data = json.loads(json1_str)

for dict in json1_data:
    for d in dict["objects"]:
        x = d["point"]["x"]
        y = d["point"]["y"]
        print(x,y)           # demo, you may use it to create your own data strucure

# flat list of all (x,y) tuples of all dicts in the json file        
print([(d["point"]["x"], d["point"]["y"]) for d in dict["objects"] for dict in json1_data])  

Answer 2

你有一個對象數組，每個 object 都有點的鍵值對，同樣你有 x 和 y 的鍵值對，你可以像這樣訪問它：

for object in objects:
    x = object["point"]["x"]
    y = object["point"]["y"]
    print("x = " + str(x) + " y = " + str(y))