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[英]Sorting a dictionary with lists as values, according to an element from the list
[英]How to create a dictionary from a list where the count of each element is the key and values are the lists of the according element?
例如:
list = [1,2,2,3,3,3,4,4,4,4]
output 應該是:
{1:[1],2:[2,2],3:[3,3,3],4:[4,4,4,4]}
其中 key = 1 是元素 1 的計數,而 value 是包含所有計數為 1 的元素的列表,依此類推。
以下代碼創建了三個字典,其中多次出現相同計數的情況以不同方式處理:
l = [1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 44, 44, 44, 44]
d_replace = dict()
d_flat = dict()
d_nested = dict()
for item in set(l):
elements = list(filter(lambda x: x == item, l))
key = len(elements)
d_replace[key] = elements
d_flat.setdefault(key, list()).extend(elements)
d_nested.setdefault(key, list()).append(elements)
print('Dictionary with replaced elements:\n', d_replace)
print('\nDictionary with a flat list of elements\n', d_flat)
print('\nDictionary with a nested lists of elements\n', d_nested)
Dictionary with replaced elements:
{1: [1], 2: [2, 2], 3: [3, 3, 3], 4: [44, 44, 44, 44]}
Dictionary with a flat list of elements
{1: [1], 2: [2, 2], 3: [3, 3, 3], 4: [4, 4, 4, 4, 44, 44, 44, 44]}
Dictionary with a nested lists of elements
{1: [[1]], 2: [[2, 2]], 3: [[3, 3, 3]], 4: [[4, 4, 4, 4], [44, 44, 44, 44]]}
d_replace
:相應的元素列表被覆蓋。d_flat
:包含具有相應計數的元素的單個列表d_nested
:包含具有相應計數的元素列表列表您可以嘗試將字典理解與過濾器或列表理解一起使用
ls = [1,2,2,3,3,3,4,4,4,4]
print({ls.count(i): [el for el in ls if el == i] for i in set(ls)})
或者
print({ls.count(i): list(filter(lambda x: x == i, ls)) for i in set(ls)})
Output
{1: [1], 2: [2, 2], 3: [3, 3, 3], 4: [4, 4, 4, 4]}
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