從多個列表創建字典，其中每個列表沒有一個鍵的值，但每個列表都有所有鍵的值

Question

我有如下列表：

key1=['A','B','C']
key2=['X','Y','Z']
entry1=['x1','y1','z1']
entry2=['x2','y2','z2']
entry3=['x3','y3','z3']

我希望我的字典具有以下格式的項目：

mydict={'A':{'X':'x1','Y':'y1','Z':'z1'},'B':{'X':'x2','Y':'y2','Z':'z2'},'C':{'X':'x3','Y':'y3','Z':'z3'}}

有人可以幫忙嗎？？

Answer 1

如果您從將三個entry列表變成一個列表開始，會更容易。 然后你可以用key1列出zip得到：

entries = [entry1, entry2, entry3]
mydict = {
    k1: {k2: e for k2, e in zip(key2, entry)}
    for k1, entry in zip(key1, entries)
}

Answer 2

這是您可以使用嵌套字典理解的：

key1=['A','B','C']
key2=['X','Y','Z']
entry1=['x1','y1','z1']
entry2=['x2','y2','z2']
entry3=['x3','y3','z3']

entries = [entry1, entry2, entry3]

my_dict = {k1:{k2:v for k2,v in zip(key2,entry)} for k1,entry in zip(key1,entries)}

print(my_dict)

Output：

{'A': {'X': 'x1', 'Y': 'y1', 'Z': 'z1'}, 'B': {'X': 'x2', 'Y': 'y2', 'Z': 'z2'}, 'C': {'X': 'x3', 'Y': 'y3', 'Z': 'z3'}}