提取以字典中的鍵命名的未指定數量的字典（Python）

Question

晚上好，

相信一切都很好。

客觀的

我正在嘗試將字典分解為每個鍵的單獨字典； 每個新字典的值都是空白的。 稍后將使用 zip function 列表填充字典。

我的嘗試

初始列表 (list_towers) 將包含不同數量的值和未指定數量的重復值。 下面代碼中的值對於我的問題是有限的。

刪除所有重復值后，我留下了一個列表 (unique_towers)，然后將其壓縮到字典 (unique_towers_dict) 中。 所有鍵都有空白值。

我想不出一個 for 循環來遍歷 unique_towers_dict 以為每個鍵創建一個單獨的字典。

任何反饋將不勝感激！

我的注釋代碼如下

from collections import OrderedDict


#The list in reality would have a varying number of values, and an unspecified number of duplicate values
list_towers = ["Tower1", "Tower1", "Tower2", "Tower3", "Tower3", "Tower4", "Tower5", "Tower5"]

print(f"Complete list of Tower values: {list_towers}\n") #prints list of towers; includes duplicates

unique_num_towers = len(set(list_towers)) #extract number of unique values in the set
print(f"Number of Unique Towers: {unique_num_towers}") #prints the unique number of towers

unique_towers = (set(list_towers)) #extracts a unique values from list_towers into the set unique_towers
unique_towers = list(unique_towers) #convert set unique_towers into a list
unique_towers.sort() #sort the list in ascending order
print(f"Names of unique towers in list: {unique_towers}\n")

unique_towers_dict = {} #create an empty dictionary unique_towers_dict
for unique_towers in zip(unique_towers): #assign the lists to the dict
    unique_towers_dict[unique_towers] = [] #assign unique_towers as key; values are empty


print(f"Nested Dictionary: {unique_towers_dict}") #print dictionary; shows empty values; keys are in ascending order

#I can't figure out a for loop to iterate through the unique_towers_dict to create a separate dictionary for each key

Answer 1

如果我理解正確，這個循環應該得到正確的答案：

d = {}
for x in unique_towers_dict.keys():
    d[x[0]] = {}

print ("\n", d)

Output

{'Tower1': {}, 'Tower2': {}, 'Tower3': {}, 'Tower4': {}, 'Tower5': {}}