[英]how can i find the location next to a randomly generated location
我正在開發一個迷宮生成器,主要使用隨機模塊並在網格上生成圖塊。 現在我正試圖防止 2 x 2s,因為我認為這是浪費空間但是如果我嘗試計算我創建的隨機圖塊旁邊的位置,我會得到一個“列表索引超出范圍”錯誤
import random
end = 90
i = 0
while i < end:
RandomRow = random.randint(0, MazeSize - 1)
RandomColumn = random.randint(0, MazeSize - 1)
Extra1 = RandomRow + 1
Extra2 = RandomRow - 1
Extra3 = RandomColumn + 1
Extra4 = RandomColumn - 1
if not Grid[RandomColumn][RandomRow]:
if not Grid[RandomColumn][RandomRow + 1]:
TempTile = MapTile('walls', RandomColumn, RandomRow)
Grid[RandomColumn][RandomRow].append(TempTile)
else:
end += 1
i += 1
'RandomRow + 1' 是一個測試以及額外的 1、2、3 和 4,但它們都沒有工作
import pygame
import random
import time
pygame.init()
clock = pygame.time.Clock()
Screen = pygame.display.set_mode([710, 710])
Done = False
MazeSize = 10
TileWidth = 60
TileMargin = 10
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
RED = (255, 0, 0)
BLUE = (0, 0, 255)
class MapTile(object):
def __init__(self, Name, Column, Row):
self.Name = Name
self.Column = Column
self.Row = Row
class Character(object):
def __init__(self, Name, Column, Row):
self.Name = Name
self.Column = Column
self.Row = Row
Maze.update()
class Maze(object): #The main class; where the action happens
global MapSize
Grid = [[None for col in range(11)] for row in range(11)]
# Creating grid
for Row in range(MazeSize):
Grid.append([])
for Column in range(MazeSize):
Grid[Row].append([])
#making walls
end = 9
i = 0
while i < end:
RandomRow = random.randint(0, MazeSize - 1)
RandomColumn = random.randint(0, MazeSize - 1)
Extra1 = RandomRow + 1
Extra2 = RandomRow - 1
Extra3 = RandomColumn + 1
Extra4 = RandomColumn - 1
if not Grid[RandomColumn][RandomRow]:
if not Grid[RandomColumn][RandomRow + 1]:
TempTile = 'x'
Grid[RandomColumn][RandomRow] = (TempTile)
else:
end += 1
i += 1
#making the whole grid flat land
for Row in range(MazeSize):
for Column in range(MazeSize):
TempTile = MapTile('path', Column, Row)
Grid[Column][Row] = (TempTile)
Maze = Maze()
run = True
while run:
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
Screen.fill(BLACK)
for Row in range(MazeSize):
for Column in range(MazeSize):
for i in range(1):
Color = WHITE
if len(Maze.Grid[Column][Row]) == 2:
Color = RED
if len(Maze.Grid[Column][Row]) >= 3:
Color = BLUE
pygame.draw.rect(Screen, Color, [(TileMargin + TileWidth) * Column + TileMargin,
(TileMargin + TileWidth) * Row + TileMargin,
TileWidth,
TileWidth])
clock.tick(60)
pygame.display.flip()
pygame.quit()
這是整個代碼(問題在底部)當我開始更改網格時,我必須更改一些東西才能使其正常工作,但是現在我陷入了這個錯誤
Traceback(最近一次調用最后一次):文件“C:\Users\faith\OneDrive\Desktop\websites\maze generator.py”,第 88 行,在 if len(Maze.Grid[Column][Row]) == 2 中: TypeError:“MapTile”類型的 object 沒有 len()
如果您嘗試在空列表上評估Grid[RandomColumn][RandomRow]
,則會收到IndexError: list index out of range
。
您可以使用填充為None
的 10x10 數組啟動 Grid :
Grid = [[None for col in range(10)] for row in range(10)]
這會給你一個結果(不確定它是否是你想要的):
import random
MazeSize = 10
Grid = [[None for col in range(11)] for row in range(11)]
end = 90
i = 0
while i < end:
RandomRow = random.randint(0, MazeSize - 1)
RandomColumn = random.randint(0, MazeSize - 1)
if not Grid[RandomColumn][RandomRow]:
if not Grid[RandomColumn][RandomRow + 1]:
TempTile = 'x'
Grid[RandomColumn][RandomRow] = TempTile
else:
end += 1
i += 1
for i in Grid:
print(i)
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