[英]Linq Group by Complex Object (E.G list element of object)
我有一個如下所示的 object;
var json = @"{
'TableNumber': '3',
'TableId': '81872d39-9480-4d2d-abfc-b8e4f33a43b6',
'tableMenuItems': [
{
'Id': '4664a2d3-c0af-443d-8af5-2bd21e71838b',
'Name': 'Bonfile',
'tableMenuItemCondiment': [
{
'Id': '9b1f01a0-0313-46b6-b7f1-003c0e846136',
'Name': 'Kekikkli',
'Price': 0
},
{
'Id': '38a9cce6-f20c-4f78-b6c9-c15e79ecc8f1',
'Name': 'mayonez',
'Price': 0
},
{
'Id': 'cb3a7811-668b-4e45-bce3-e6b2b13af9e1',
'Name': 'Rare',
'Price': 0
}
],
'Price': 45,
'Count': 1
},
{
'Id': '4664a2d3-c0af-443d-8af5-2bd21e71838b',
'Name': 'Bonfile',
'tableMenuItemCondiment': [
{
'Id': 'c3c62f7d-987d-4523-849c-932334db4e4f',
'Name': 'Kekikkli',
'Price': 0
},
{
'Id': 'cbb16028-6e77-4e4b-a1c9-d969e804f093',
'Name': 'mayonez',
'Price': 0
},
{
'Id': '16f9efc2-73d3-4a09-87fc-e1fb76957ed2',
'Name': 'Rare',
'Price': 0
}
],
'Price': 45,
'Count': 1
}
],
'TotalPrice': 90
}";
正如您在上面看到的,object 具有作為 tableMenuItems 的列表元素。 tableMenuItems 屬性中有兩個 object,這是完全相同的。 我想像下面這樣對這個 object 進行分組;
var json = @"{
'TableNumber': '3',
'TableId': '81872d39-9480-4d2d-abfc-b8e4f33a43b6',
'tableMenuItems': [
{
'Id': '4664a2d3-c0af-443d-8af5-2bd21e71838b',
'Name': 'Bonfile',
'tableMenuItemCondiment': [
{
'Id': '9b1f01a0-0313-46b6-b7f1-003c0e846136',
'Name': 'Kekikkli',
'Price': 0
},
{
'Id': '38a9cce6-f20c-4f78-b6c9-c15e79ecc8f1',
'Name': 'mayonez',
'Price': 0
},
{
'Id': 'cb3a7811-668b-4e45-bce3-e6b2b13af9e1',
'Name': 'Rare',
'Price': 0
}
],
'Price': 90,
'Count': 2
}
],
'TotalPrice': 90
}";
如您所見,如果兩個 tablemenuitems 相同並且它們的調味品相同我將它們分組。 我為 gruping 制作了一些 IEqualityComparer,但它不起作用,我除外。
這是我在下面的鏈接中看到的;
https://do.netfiddle.net/QQFfIy
我不明白我做錯了什么
1 ) 我創建了我的課程以滿足 json,
public class MyTable {
public string TableNumber { get; set; }
public string TableId { get; set; }
public List<TableMenu> tableMenuItems { get; set; }
public int TotalPrice { get; set; }
}
public class TableMenu {
public string Id { get; set; }
public string Name { get; set; }
public List<TableMenuItemCondiment> tableMenuItemCondiment { get; set; }
public int Price { get; set; }
public int Count { get; set; }
}
public class TableMenuItemCondiment {
public string Id { get; set; }
public string Name { get; set; }
public int Price { get; set; }
}
2)然后我通過NewtonSoft反序列化了object,
MyTable myTable = JsonConvert.DeserializeObject<MyTable>(json);
3)轉換為object,
MyTable result = new MyTable() {
TableNumber = myTable.TableNumber,
TableId = myTable.TableId,
tableMenuItems = myTable.tableMenuItems.GroupBy(x => x.Id).Select(x => new TableMenu() {
Id = x.Key,
Name = x.First()?.Name,
tableMenuItemCondiment = x.SelectMany(a=>a.tableMenuItemCondiment).GroupBy(z => z.Name).Select(z => new TableMenuItemCondiment() {
Id = z.First()?.Id,
Name = z.Key,
Price = z.Sum(t => t.Price)
}).ToList(),
Price = x.Sum(t => t.Price),
Count = x.Sum(t => t.Count)
}).ToList(),
TotalPrice = myTable.TotalPrice
};
4 ) 最后序列化object,看是否如你所願給出響應,
string output = JsonConvert.SerializeObject(result);
5)打印output,
Console.WriteLine(output);
Console.ReadKey();
Output:
{ "TableNumber":"3",
"TableId":"81872d39-9480-4d2d-abfc-b8e4f33a43b6",
"tableMenuItems":[
{
"Id":"4664a2d3-c0af-443d-8af5-2bd21e71838b",
"Name":"Bonfile",
"tableMenuItemCondiment":[
{
"Id":"9b1f01a0-0313-46b6-b7f1-003c0e846136",
"Name":"Kekikkli",
"Price":0
},
{
"Id":"38a9cce6-f20c-4f78-b6c9-c15e79ecc8f1",
"Name":"mayonez",
"Price":0
},
{
"Id":"cb3a7811-668b-4e45-bce3-e6b2b13af9e1",
"Name":"Rare",
"Price":0
}
],
"Price":90,
"Count":2
}
],
"TotalPrice":90 }
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