[英]how to print multiple separate for loop outputs as columns in bash
我有一個腳本,我想讀取二進制值列表並將它們打印如下(在列中,但不一定相應標記)-
binary decimal truncated truncated-decimal
等等
- 隨后的列被越來越高的值順序截斷。 到目前為止,我所擁有的最多只有 3 個。
for z in {1..3};
do
p2=$(for n2 in $(cat binary_primes.txt );
do echo $n2;
done) #prints original values
p10=$(for n10 in $(echo $p2);
do echo "ibase=2;$n10;obase=10" | bc;
done) #prints original values in decimal
a2=$(for y in $(cat binary_primes.txt );
do
xx=${y:0:${#y}-$z} 2>/dev/null; echo
$xx;
done) #original value truncated by 1 bit
a10=$(for y2 in $(echo $a2);
do echo "ibase=2;$y2;obase=10" | bc;
done) #the latter in decimal
b2=$(for x in $(cat binary_primes.txt );
do xx=${x:0:${#x}-$z} 2>/dev/null;
echo $xx;
done) #original value truncated by 2 bits
b10=$(for x2 in $(echo $b2);
do echo "ibase=2;$x2;obase=10" | bc;
done) #the latter in decimal
c2=$(for w in $(cat binary_primes.txt );
do xx=${w:0:${#w}-$z} 2>/dev/null;
echo $xx;
done) #original value truncated by 3 bits
c10=$(for w2 in $(echo $c2);
do echo "ibase=2;$w2;obase=10" | bc;
done) #the latter in decimal
echo $p2 $p10 $a2 $a10 $b2 $b10 $c2 $c10;
done
我嘗試過使用 column -t、column -x、paste 和 join,但我不斷收到錯誤。 我想避免輸出到一堆文本文件然后閱讀它們——理想情況下保持這個獨立。
我還想知道是否有人能告訴我最干凈的方法是簡單地忽略超過原始值位數的截斷值實例(即,將 100010101 截斷為大於“9”的值,等等)。 - 這就是所有 2>/dev/null 都試圖避免的(笨拙地,我知道)。
這是引用的文本文件的前 30 行,也是唯一需要的文件(理想情況下):
100111101010011111101
100111101010011101001
100111101010011011001
100111101010011000101
100111101010010111111
100111101010010110101
100111101010010101111
100111101010010010001
100111101010001111111
100111101010001100001
100111101010001010101
100111101010001001101
100111101010000101011
100111101010000100011
100111101010000000001
100111101001111111011
100111101001111111001
100111101001111101111
100111101001111101101
100111101001110110011
100111101001110110001
100111101001110100111
100111101001110011111
100111101001110010101
100111101001110001111
100111101001110001101
100111101001101111011
100111101001101110101
100111101001101100011
100111101001101011001
output 文件會更長,因為它會打印,但是基於原始數字擴展可以使用許多截斷,我最終希望 go 達到 21(文件中最大的位權重),但這里又是前 30 行為了比較:
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 10011110101001111110 649854
100111101010011111101 1299709 1001111010100111111 324927
100111101010011111101 1299709 100111101010011111 162463
100111101010011111101 1299709 10011110101001111 81231
100111101010011111101 1299709 1001111010100111 40615
100111101010011111101 1299709 100111101010011 20307
100111101010011111101 1299709 10011110101001 10153
100111101010011111101 1299709 1001111010100 5076
100111101010011111101 1299709 100111101010 2538
100111101010011111101 1299709 10011110101 1269
100111101010011111101 1299709 1001111010 634
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 10011110 158
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 100111 39
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 1001 9
100111101010011111101 1299709 100 4
100111101010011111101 1299709 10 2
100111101010011111101 1299709 1 1
100111101010011101001 1299689 100111101010011101001 1299689
100111101010011101001 1299689 10011110101001110100 649844
100111101010011101001 1299689 1001111010100111010 324922
100111101010011101001 1299689 100111101010011101 162461
100111101010011101001 1299689 10011110101001110 81230
100111101010011101001 1299689 1001111010100111 40615
100111101010011101001 1299689 100111101010011 20307
100111101010011101001 1299689 10011110101001 10153
100111101010011101001 1299689 1001111010100 5076
最終,我希望有一個第 5 列,它不會在標准輸出中,但會在腳本運行時生成將打印:
1299709: 1299709
649854: 2 3 3 79 457
324927: 3 3 79 457
162463: 7 23209
81231: 3 27077
40615: 5 8123
20307: 3 7 967
10153: 11 13 71
5076: 2 2 3 3 3 47
2538: 2 3 3 3 47
1269: 3 3 3 47
634: 2 317
317: 317
158: 2 79
79: 79
39: 3 13
19: 19
9: 3 3
4: 2 2
2: 2
1:
1299689: 1299689
649844: 2 2 13 12497
324922: 2 13 12497
162461: 13 12497
81230: 2 5 8123
40615: 5 8123
20307: 3 7 967
10153: 11 13 71
5076: 2 2 3 3 3 47
一旦 greped+awked 只有這些是素數:
1299709: 1299709
317: 317
79: 79
19: 19
2: 2
1299689: 1299689
我遇到的另一個問題是我不確定如何使兩列繼續打印相同的值,而其他列遞增。
即:
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 10 2
而不是這個:
100111101010011111101 1299709 100111101010011111101 1299709
100111101010000101011 1299499 100111101 317
100111101010000000001 1299457 1001111 79
100111101001111111001 1299449 10011 19
100111101001110110011 1299379 10 2
所以我最終想要做的完整最終結果的前 30 行是:
100111101010011111101 1299709 100111101010011111101 1299709
100111101010011111101 1299709 100111101 317
100111101010011111101 1299709 1001111 79
100111101010011111101 1299709 10011 19
100111101010011111101 1299709 10 2
100111101010011101001 1299689 100111101010011101001 1299689
100111101010011101001 1299689 100111101 317
100111101010011101001 1299689 1001111 79
100111101010011101001 1299689 10011 19
100111101010011101001 1299689 10 2
100111101010011011001 1299673 100111101010011011001 1299673
100111101010011011001 1299673 100111101 317
100111101010011011001 1299673 1001111 79
100111101010011011001 1299673 10011 19
100111101010011011001 1299673 10 2
100111101010011000101 1299653 100111101010011000101 1299653
100111101010011000101 1299653 100111101 317
100111101010011000101 1299653 1001111 79
100111101010011000101 1299653 10011 19
100111101010011000101 1299653 10 2
100111101010010111111 1299647 100111101010010111111 1299647
100111101010010111111 1299647 100111101 317
100111101010010111111 1299647 1001111 79
100111101010010111111 1299647 10011 19
100111101010010111111 1299647 10 2
100111101010010110101 1299637 100111101010010110101 1299637
100111101010010110101 1299637 100111101 317
100111101010010110101 1299637 1001111 79
100111101010010110101 1299637 10011 19
100111101010010110101 1299637 10 2
該要求似乎從文件中讀取(二進制)數字,並為每個值生成多行顯示 (value, value/2, value/4, ..., value/(2^n) 的十進制和二進制表示))
解決方案是純 bash,這意味着它對於相對較大的文件會表現良好(不會重復調用 'bc' 實用程序)。 二進制轉十進制是使用 bash 算術表達式。
#! /bin/bash
while read b ; do
# Convert binary 'b' to decimal 'd'
d=$((2#$b))
bb=$b
dd=$d
b_len=${#b}
while (( dd > 0 )) ; do
printf "%s %d %-${b_len}s %d\n" $b $d $bb $dd
dd=$((dd/2))
bb=${bb:0:${#bb}-1}
done
done < binary_primes.txt
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