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[英]Deserializing a string XML and error:There is an error in XML document (1, 2)
[英]There is an error in XML document (0, 0) - Error Deserializing XML to object
請建議我如何將 map 響應轉換為 class 因為從我遇到的每個示例中,身體總是沒有像core:transactionResponse
這樣的符號
我的代碼:
string fileName = @"C:\Users\Lenovo\Downloads\GLResponseXml.xml";
XDocument xDoc = XDocument.Load(fileName);
var unwrappedResponse = xDoc.Descendants((XNamespace)"http://schemas.xmlsoap.org/soap/envelope/" + "Body")
.First()
.FirstNode;
XmlSerializer xmlSerializer = new XmlSerializer(typeof(TransactionResponse));
TransactionResponse response = (TransactionResponse)xmlSerializer.Deserialize(xDoc.Descendants((XNamespace)"http://schemas.xmlsoap.org/soap/envelope/" + "Body")
.First()
.FirstNode
.CreateReader()
);
為了取消這個 soap xml:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:dpss0="bons">
<soapenv:Header/>
<soapenv:Body>
<core:transactionResponse xmlns:bo="http://service.example.co.id/core/bo" xmlns:core="http://service.example.co.id/core">
<response>
<header>
<coreJournal>149326</coreJournal>
</header>
<content xsi:type="bo:OKMessage">
<message/>
</content>
</response>
</core:transactionResponse>
</soapenv:Body>
</soapenv:Envelope>
但我收到此錯誤: InvalidOperationException: <transactionResponse xmlns='http://service.example.co.id/core'> was not expected.
我正在將響應映射到這個 class:
public class GLXmlResponse
{
[XmlRoot(ElementName = "response")]
public class Response
{
[XmlElement(ElementName = "header")]
public Header Header { get; set; }
[XmlElement(ElementName = "content")]
public Content Content { get; set; }
}
[XmlRoot(ElementName = "header")]
public class Header
{
[XmlElement(ElementName = "coreJournal")]
public string CoreJournal { get; set; }
}
[XmlRoot(ElementName = "content")]
public class Content
{
[XmlElement(ElementName = "message")]
public string Message { get; set; }
[XmlAttribute(AttributeName = "type", Namespace = "http://www.w3.org/2001/XMLSchema-instance")]
public string Type { get; set; }
}
[XmlRoot(ElementName = "transactionResponse", Namespace = "http://service.example.co.id/core")]
public class TransactionResponse
{
[XmlElement(ElementName = "response")]
public Response Response { get; set; }
[XmlAttribute(AttributeName = "bo", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Bo { get; set; }
[XmlAttribute(AttributeName = "core", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Core { get; set; }
}
[XmlRoot(ElementName = "Body", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
public class Body
{
[XmlElement(ElementName = "transactionResponse", Namespace = "http://service.example.co.id/core")]
public TransactionResponse TransactionResponse { get; set; }
}
[XmlRoot(ElementName = "Envelope", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
public class Envelope
{
[XmlElement(ElementName = "Header", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
public string Header { get; set; }
[XmlElement(ElementName = "Body", Namespace = "http://schemas.xmlsoap.org/soap/envelope/")]
public Body Body { get; set; }
[XmlAttribute(AttributeName = "soapenv", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Soapenv { get; set; }
[XmlAttribute(AttributeName = "soapenc", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Soapenc { get; set; }
[XmlAttribute(AttributeName = "xsd", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Xsd { get; set; }
[XmlAttribute(AttributeName = "xsi", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Xsi { get; set; }
[XmlAttribute(AttributeName = "dpss0", Namespace = "http://www.w3.org/2000/xmlns/")]
public string Dpss0 { get; set; }
}
}
需要幫助獲得 class object 正確
我無法重現您所看到的確切錯誤,因此您可能希望從最小的重現中進行檢查; 我在用着:
var env = (GLXmlResponse.Envelope)new XmlSerializer(typeof(GLXmlResponse.Envelope))
.Deserialize(new StringReader(xml));
System.Console.WriteLine(env.Body.TransactionResponse.Response.Header.CoreJournal);
在哪里:
string xml = @"<soapenv:Envelope xmlns:soapenv=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:soapenc=""http://schemas.xmlsoap.org/soap/encoding/"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:dpss0=""bons"">
<soapenv:Header/>
<soapenv:Body>
<core:transactionResponse xmlns:bo=""http://service.example.co.id/core/bo"" xmlns:core=""http://service.example.co.id/core"">
<response>
<header>
<coreJournal>149326</coreJournal>
</header>
<content xsi:type=""bo:OKMessage"">
<message/>
</content>
</response>
</core:transactionResponse>
</soapenv:Body></soapenv:Envelope>";
它只有一個null
用於.Response
。 原因是這實際上是在空命名空間中(前綴不是繼承的),所以你需要
[XmlElement(ElementName = "response", Namespace = "")]
public Response Response { get; set; }
但是,這會導致OKMessage
中的 OKMessage 出現問題。如果我注釋掉<content>
,那么它會起作用,我可以看到 output 149326
。
但是,開始時可能更簡單,只需將 xml 復制到剪貼板,編輯 -> 選擇性粘貼 -> 將 XML 作為類粘貼,然后查看生成的內容,然后從那里開始工作。
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