SQL MAX 和按日期和產品的總計

Question

需要幫助 - 我需要從表格中獲得所有日子中每天貢獻最多的頁面的百分比。 我需要按日期、頁面、占該日期總訂閱量的百分比、占總時間的百分比來顯示它

這是表：

P_date |    PageName | Subscribes
02/05/2020  page1   258
05/05/2020  page1   10 
01/07/2020  page1   236
02/05/2020  page2   15
02/05/2020  page3   14
05/05/2020  page2   13
05/05/2020  page3   223

這是我的代碼：

select P_date,  
    max(total_subs) as Max_subs, 
    format((max(total_subs)/sum(total_subs)),'.00%') as 'Percentage out of total that day',
    format((max(total_subs) / (select sum(total_subs) from 
    table1)),'.00%') as  'Percentage out of total'  from table1
group by P_date order by 'Percentage out of total' desc

輸出是：

但我還需要添加頁面名稱 - 我需要每天顯示 1 個最佳頁面？

Answer 1

在 MSSQL 中，您可以執行以下操作：

SELECT * /*specify desired columns here*/
( 
  SELECT * FROM ( 
    SELECT table1.*, ROW_NUMBER() OVER(PARTITION BY P_date ORDER BY Subscribes DESC) as row_num
    FROM table1 )
  WHERE row_num = 1
) as bestPagePerDate
JOIN (
select P_date,  
    max(total_subs) as Max_subs, 
    format((max(total_subs)/sum(total_subs)),'.00%') as 'Percentage out of total that day',
    format((max(total_subs) / (select sum(total_subs) from 
    table1)),'.00%') as  'Percentage out of total'  from table1
group by P_date order by 'Percentage out of total' desc
) as yourQuery
ON yourQuery.P_date = bestPagePerDate.P_date 

Answer 2

您可以按如下方式使用窗口函數：

select p_date, page_name, total_subs, 1
    1.0 * total_subs / total_subs percentage_day, 
    1.0 * total_subs / sum_total_subs percentage_overall
from (
    select t.*,
        row_number() over(partition by p_date order by total_subs desc) rn
        sum(total_subs) over(partition by p_date) p_date_total_subs,
        sum(total_subs) over() overal_total_subs 
    from table1 t
) t
where rn = 1

Answer 3

您可以使用每天最佳頁面的查詢進行子查詢，並將其顯示在您的全局查詢中。