[英]Select from SUM() of multiple columns and join in postgreSQL
我有一個名為 DETAILS 的表,它有 5 個數字列 DETAILS(id, key2, key3, num1, num2, num3, num4, num5)。 id、key2 和 key3 的組合是主鍵。 每個 id 可能有多行。
我的要求是獲取按 id 分組的每列的前 10 個 SUM 值,如下所示。
select id
,sum(num1) val1
from details
group by id
order by sum(num1) desc nulls last
limit 10;
select id
,sum(num2) val2
from details
group by id
order by sum(num2) desc nulls last
limit 10;
select id
,sum(num3) val3
from details
group by id
order by sum(num3) desc nulls last
limit 10;
select id
,sum(num4) val4
from details
group by id
order by sum(num4) desc nulls last
limit 10;
select id
,sum(num5) val5
from details
group by id
order by sum(num5) desc nulls last
limit 10;
我需要根據下面的 id 組合上述結果
id, sum(num1), sum(num2), sum(num3), sum(num4), sum(num5)
假設第一個查詢返回
[{id: 1, val1: 50}, {id: 2, val1: 60}, {id: 3, val1: 70}]
第二個查詢返回
[{id: 3, val2: 150}, {id: 4, val2: 160}, {id: 3, val2: 170}]
結果應該是
[
{id: 1, val1: 50, val2: null},
{id: 2, val1: 60, val2: null},
{id: 3, val1: 70, val2: 150},
{id: 4, val1: null, val2: 160},
{id: 5, val1: null, val2: 170},
]
這可以通過使用 join 或其他方式的單個查詢實現嗎? 如果是這樣,我如何通過優化查詢來實現這一點?
我認為您需要對所有 5 個查詢進行 FULL OUTER JOIN:
with
cte1 as (
select id, sum(num1) val1 from details
group by id
order by sum(num1) desc nulls last limit 10
),
cte2 as (
select id, sum(num2) val2 from details
group by id
order by sum(num2) desc nulls last limit 10
),
cte3 as (
select id, sum(num3) val3 from details
group by id
order by sum(num3) desc nulls last limit 10
),
cte4 as (
select id, sum(num4) val4 from details
group by id
order by sum(num4) desc nulls last limit 10
),
cte5 as (
select id, sum(num5) val5 from details
group by id
order by sum(num5) desc nulls last limit 10
)
select coalesce(c1.id, c2.id, c3.id, c4.id, c5.id) id,
c1.val1, c2.val2, c3.val3, c4.val4, c5.val5
from cte1 c1
full outer join cte2 c2 on c2.id = c1.id
full outer join cte3 c3 on c3.id = c2.id
full outer join cte4 c4 on c4.id = c3.id
full outer join cte5 c5 on c5.id = c4.id
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