如何將此代碼更改為不打印未使用的硬幣=0？

Question

我正在嘗試構建一個功能，在人們輸入金額后，它將顯示他們需要的最少硬幣或紙幣數量。 但這有什么方法可以讓我改變它，這樣它就不會打印未使用硬幣的名稱和數量？ （作為初學者）感謝您的幫助！ （可以用for循環來處理嗎？）

Answer 1

不是為每個演示保留一個變量，而是保留一個 dict 並根據所使用的面額更新 key: val 。 看代碼

amount=int(input('Enter an amount: '))

denominations = dict()

print('Total number of notes/coins=')

if amount>=1000:
    denominations['1000'] = amount//1000
    amount%=1000    
if amount>=500:
    denominations['500'] = amount//500
    amount= amount%500
if amount>=100:
    denominations['100'] = amount//100
    amount= amount%100
if amount>=50:
    denominations['50'] = amount//50
    amount= amount%50    
if amount>=20:
    denominations['20'] = amount//20
    amount= amount%20    
if amount>=10:
    denominations['10'] = amount//10
    amount= amount%10
if amount>=5:
    denominations['5'] = amount//5
    amount= amount%5   
if amount>=2:
    denominations['2'] = amount//2
    amount= amount%2    
if amount>=1:
    denominations['1'] = amount//1

for key, val in denominations.items():
    print(f"{key}: {val}")


Enter an amount: 523
Total number of notes/coins=
500: 1
20: 1
2: 1
1: 1

如果您使用如下所示的簡單邏輯，您可以減少代碼行數，

def find_denominations():
    
    amount=int(input('Enter an amount: '))
    
    denominations = dict()
    
    DENOMINATIONS = [1000, 500, 100, 50, 20, 10, 5, 2, 1]
       
    print('Total number of notes/coins=')
    
    for d in DENOMINATIONS:
        if amount >= d:
            denominations[d] = amount // d
            amount %= d

    for key, val in denominations.items():
        print(f"{key}: {val}") 

Answer 2

使用 while 循環而不是 for 循環的 Sreerams 的類似實現：

amount = int(input("Enter an amount: "))

counter = amount
pos = 0
notes = [1000, 500, 100, 50, 20, 10, 5, 2, 1]
output = []

while counter > 0:

    remainder = counter % notes[pos]
    sub = counter - remainder
    num = int(sub / notes[pos])
    counter -= sub
    output.append({notes[pos]: num})
    pos += 1

print("Total number of notes/coins=")

for r in output:
    for k,v in r.items():
        if v > 0:
            print("{}: {}".format(k, v))

請注意，Sreerams 代碼優於我的代碼，它更易於閱讀並且在規模上的性能更高。

Answer 3

循環可用於遍歷筆記列表，並在循環內部，如果發現任何筆記被計數，則可以打印。

notes=[1000,500,100,50,20,10,5,2,1]

amount=int(input('Enter an amount: '))

print('Total number of notes/coins=')

for notesAmount in notes:
    if amount>=notesAmount:
       notesCount=amount//notesAmount
       amount%=notesAmount
       if notesCount>0:
          print(notesAmount, ":", notesCount)