python多線程中，如何yield for result和返回線程值？

Question

運行此代碼，我得到以下日志，而不是future值，我得到線程 object。產生f的結果並最終返回帶值的Y的正確方法是什么？

Y = []
process_pool = ThreadPoolExecutor(4)
f = partial(some_func, *args)
for i in range(1000):
    future = process_pool.submit( f ,i)
    print(future)
    Y.append(future)
return Y 

日志：

<Future at 0x7f82c8ebf390 state=running>
<Future at 0x7f82cb636f10 state=running>
<Future at 0x7f82cb0af090 state=running>
<Future at 0x7f82cb0af190 state=running>
<Future at 0x7f82cb0af350 state=pending>
<Future at 0x7f82cb0ae350 state=pending>
...

是：

[<Future at 0x7f82c8ebf390 state=finished raised NameError>, <Future at 0x7f82cb636f10 state=finished raised NameError>, <Future at 0x7f82cb0af090 state=finished raised NameError>, <Future at 0x7f82cb0af190 state=finished raised NameError>, <Future at 0x7f82cb0af350 state=finished raised NameError>, <Future at 0x7f82cb0ae350 state=finished raised NameError>, <Future at 0x7f82cb0ae290 state=running>, <Future at 0x7f82cb0aea10 state=finished raised NameError>, <Future at 0x7f82cb0ae950 state=running>,...]

Answer 1

兩種簡單的方法是：1-讓您的 f() 將結果存儲在 class 或 class 實例變量中； 2- 使用 concurrent.futures.as_completed()

import concurrent.futures

Y = []
l_tasks = [] 
with concurrent.futures.ThreadPoolExecutor() as executor:
    for i in range(1000):
        l_tasks.append(executor.submit(f, i))
    for task in concurrent.futures.as_completed(l_tasks):
        Y.append(task.result())