[英]Populate one DropDown List from another selected value
我有兩個下拉列表,我像這樣填充它們:
private List<Client> Client()
{
var allClients= _db.tboClient.Select(x =>
new Tecnico
{
Id = x.Id,
Nome = x.Nome
}).ToList();
return allClients;
}
private List<Pricerice> Price()
{
var allPrice = _db.tboPrice.Select(x =>
new Cliente
{
Id = x.Id,
Nome_azienda = x.Nome_azienda
}).ToList();
return allPrice ;
}
然后是一些我記得Client()
和Price()
。 我像這樣加載視圖:
public IActionResult Create()
{
ViewBag.Price= Pricei();
ViewBag.Clienti = CLienti();
return View();
}
這是 HTML:
<div class="dropdown">
@Html.DropDownListFor(m => m.CLienti, new SelectList(ViewBag.CLienti, "Id", "Nome_azienda"), new { @id = "ddlCLienti", @class = "btn btn-primary dropdown-toggle mr-3" })
</div>
<div class="dropdown">
@Html.DropDownListFor(m => m.Price, new SelectList(ViewBag.Price, "Id", "Nome"), new { @id = "ddlClienti", @class = "btn btn-primary dropdown-toggle mr-3" })
</div>
我想根據從第一個下拉列表中選擇的值填充第二個(價格)下拉列表。
我想根據從第一個下拉列表中選擇的值填充第二個(價格)下拉列表。
為了實現實現級聯下拉列表的上述要求,您可以嘗試根據“ddlCLienti” dorpdown change
事件上第一個下拉列表的先前選擇來填充第二個下拉列表,如下所示。
<script>
$(function () {
$("select#ddlCLienti").change(function () {
var CLienti = $(this).val();
$("select#ddlPrice").empty();
$.getJSON(`/your_controller_name_here/GetPriceBySelectedCLienti?CLienti=${CLienti}`, function (data) {
//console.log(data);
$.each(data, function (i, item) {
$("select#ddlPrice").append(`<option value="${item.id}">${item.nome}</option>`);
});
});
})
})
</script>
GetPriceBySelectedCLienti
操作方法
public List<Price> GetPriceBySelectedCLienti(int CLienti)
{
//query data based on selected CLienti
//...
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