[英]Splitting Integers that are inside a List in Python
我將如何獲取這樣的整數列表:
[12,23,32]
並讓它在打印時具有輸出:
[1, 2, 2, 3, 3, 2]
對於那些因為“編寫代碼”而選擇不提供幫助的人,請看這里:
sequence = [12, 23, 32]
print([int(i) for i in sequence])
您可以使用以下split
功能:
a = [12, 23, 32]
def split(l):
final_list = []
for item in l:
for elem in list(str(item)):
final_list.append(int(elem))
return final_list
print(split(a))
這應該有效:
import itertools
a = [12, 23, 32]
b = [int(z) for z in list(itertools.chain.from_iterable([list(str(x)) for x in a]))]
print(b)
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