根據 typeScript 中的多個條件過濾對象數組

Question

嗨，團隊，我有一系列對象，例如

data = [
  { name: "Pork", category: "Food", subcategory: "Meat" },
  { name: "Pepper", category: "Food", subcategory: "Vegetables" },
  { name: "Beef", category: "Food", subcategory: "Meat" },
  { name: "banana", category: "Food", subcategory: "Fruit" }
];

這里我需要根據過濾條件過濾data數組

{
   "filters":[
      {
         "filters":[
            {
               "field":"subcategory",
               "operator":"eq",
               "value":"Vegetables"
            }
         ],
         "logic":"or"
      },
      {
         "filters":[
            {
               "field":"name",
               "operator":"eq",
               "value":"Pepper"
            },
            {
               "field":"name",
               "operator":"eq",
               "value":"banana"
            }
         ],
         "logic":"or"
      }
   ],"logic":"and"
}

我可以簡單地在Kendo使用process()來做到這一點

kendo.data.Query.process(data, {
  filter: {
    logic: "and",
    filters: [{
      field: "subcategory",
      value: "Meat",
      operator: "eq"
    }],logic:"or"
  }
});

那么有沒有其他方法可以在不使用process()情況下進行這樣的過濾？

Answer 1

這種方法采用包含數組和邏輯部分的filters對象作為條件的量詞。

該數組可以包含具有filters量詞作為logic其他對象，或者具有單個屬性約束的對象，這些屬性必須匹配給定數據數組的項目。

實際上只實現了一個操作符。

 const operators = { eq: (a, b) => a === b }, quantifiers = { and: 'every', or: 'some' }, filter = ({ filters, logic }) => item => filters[quantifiers[logic]](f => 'filters' in f ? filter(f)(item) : operators[f.operator](item[f.field], f.value) ), filters = { filters: [{ filters: [{ field: "subcategory", operator: "eq", value: "Vegetables" }], logic: "or" }, { filters: [{ field: "name", operator: "eq", value: "Pepper" }, { field: "name", operator: "eq", value: "banana" }], logic: "or" }], logic: "and" }, data = [{ name: "Pork", category: "Food", subcategory: "Meat" }, { name: "Pepper", category: "Food", subcategory: "Vegetables" }, { name: "Beef", category: "Food", subcategory: "Meat" }, { name: "banana", category: "Food", subcategory: "Fruit" }], result = data.filter(filter(filters)); console.log(result);

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