[英]Changing facet labels in face_wrap() ggplot2
所以下面的代碼可以正常工作,沒有錯誤,我正在嘗試解決以下問題。
首先,我試圖更改每個圖表的組名,例如,“< 1500 美元”是指收入 1500 美元或以下的工人組等......
我嘗試了這個解決方案:更改基礎因子級別名稱,但我不斷收到此錯誤:
"錯誤:意外的 ',' in ""< 1500 Dollars",""
outflows <- Wage_Outflows
levels(outflows$wage_group)
"< 1500", "1501 ~ 2999", "3000",
levels(outflows$wage_group) <- c("< 1500 Dollars", "1501 ~ 2999 Dollars", "3000 Dollars")
text.on.each.panel <-"Dollars"
p1 = ggplot(Wage_Outflows[Wage_Outflows$wage_group=="< 1500",], aes(x = year, y = labor)) +
geom_point() +
scale_y_continuous(breaks=seq(4000000, 6500000, by = 400000)) +
facet_wrap(~ wage_group) + theme(axis.title.x = element_blank())
p2 = ggplot(Wage_Outflows[Wage_Outflows$wage_group=="1501 ~ 2999",], aes(x = year, y = labor)) +
geom_point() +
scale_y_continuous(breaks=seq(800000, 1100000, by = 20000)) +
facet_wrap(~ wage_group) + theme(axis.title.x = element_blank())
p3 = ggplot(Wage_Outflows[Wage_Outflows$wage_group=="3000",], aes(x = year, y = labor)) +
geom_point() +
scale_y_continuous(breaks=seq(50000, 120000, by = 5000)) +
facet_wrap(~ wage_group) + theme(axis.title.x = element_blank())
grid.arrange(p1, p2,p3, ncol=1)
關於第一個問題有一個看看labeller
的參數facet_wrap
功能。
對於您的第二個問題, labs
功能可能是解決方案。
p1 = ggplot(Wage_Outflows[Wage_Outflows$wage_group=="< 1500",],
aes(x = year, y = labor)) +
geom_point() +
scale_y_continuous(breaks=seq(4000000, 6500000, by = 400000)) +
labs(y = "Number of workers") +
facet_wrap(~ wage_group, labeller = labeller(wage_group = c(`< 1500` = "< 1500
dollars"))) +
theme(axis.title.x = element_blank())
也許你可以像這樣縮短你的代碼:
# Example dataset:
df <- data.frame(wage_group = rep(c("A","B","C"), each = 10),
year = 2001:2010,
labor = seq(5000,34000, 1000))
ggplot(df , aes(x = factor(year), y = labor)) +
geom_point() +
labs(y = "# of workers") +
facet_wrap(~wage_group, ncol = 1, scales = "free",
labeller = labeller(wage_group = c(`A` = "less than 1500 dollars",
`B` = "1500-2999 dollars", `C` = "more than 3000 dollars"))) +
theme(axis.title.x = element_blank())
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