[英]How do I get values of a list containing dictionary to compare with another dictionary?
這是我的字典列表
scores = [{'names':'soccer', 'power':'5'},{'names':'football', 'power':6}]
正如您所看到的,我的 I 可能在冪值中有字符串。
我的字典我想與分數值(足球)的名稱是否相等進行比較。
my_stats = {'soccer':3, 'football':2}
所以例如
for values in scores:
if my_stats(index) == "soccer" and scores(names) == "soccer":
if my_stats(value) < power(value):
return power(value) is higher
我知道這段代碼不起作用,但這是我第一次嘗試從列表中獲取字典值。 我猜我需要 2 個 for 循環? 1 代表列表,1 代表字典?
我在scores
列表中添加了更多條目以使代碼更通用。
下面的代碼將掃描完整的scores
列表,並在my_stats
找到唯一游戲的my_stats
。
scores = [{'names':'soccer', 'power':'5'},
{'names':'soccer', 'power':8},
{'names':'football', 'power':6},
{'names':'football', 'power':9}]
my_stats = {'soccer':3, 'football':2}
for score in scores:
for game,power in my_stats.items():
if score['names'] == game and int(score['power']) > power:
my_stats[game] = int(score['power'])
print (my_stats)
輸出將是:
{'soccer': 8, 'football': 9}
原始scores
列表的輸出是:
{'soccer': 5, 'football': 6}
擴展代碼
您可能還想查看此選項。 如果scores
中的游戲在my_stats
中不存在,那么下面的代碼也會將游戲添加到my_stats
scores = [{'names':'soccer', 'power':'5'},
{'names':'soccer', 'power':8},
{'names':'football', 'power':6},
{'names':'football', 'power':9},
{'names':'basketball', 'power':20}]
my_stats = {'soccer':3, 'football':2}
for score in scores:
if score['names'] in my_stats:
if int(score['power']) > my_stats[score['names']]:
my_stats[score['names']] = int(score['power'])
else:
my_stats[score['names']] = int(score['power'])
#for game,power in my_stats.items():
# if score['names'] == game and int(score['power']) > power:
# my_stats[game] = int(score['power'])
print (my_stats)
上面的代碼會給你一個輸出如下:
{'soccer': 8, 'football': 9, 'basketball': 20}
for score in scores:
if score['names'] == 'soccer':
if score['power'] == my_stats['soccer']
print('the name is soccer and the scores are even')
如果這就是你想要做的,請告訴我! :)
注意:一般來說,如果你想比較字典,我建議保持字典鍵相同。 我不確定您的目標是什么,但例如,我會將scores
結構更改為:
scores = {'power':
{'football': 5, 'soccer': 6}
}
這樣你可以這樣做:
if scores['powers']['football'] == my_stats['football']:
print('scores are the same')
首先,您可以將scores
標准化為與my_stats
類似的數據結構。 這可以像這樣完成:
>> _scores = dict(zip([item["names"] for item in a], [int(item["power"]) for item in a])
>> _scores
{'football': 6, 'soccer': 5}
然后像往常一樣從字典中獲取:
>> _scores.get("soccer")
5
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