[英]Password length through Firebase authentication
如何在密碼長度上顯示錯誤消息? 通過 Firebase 認證進行登錄。 If final EditText mpassword.mpassword.setError("密碼必須介於 8 到 15 個字符之間。"); 返回; 我曾嘗試根據密碼長度制作一個 if/else 語句,但這似乎無法正常工作。 這是我到目前為止的代碼。
package com.debatewithus.ui.login;
import android.content.Intent;
import android.os.Bundle;
import androidx.annotation.NonNull;
import androidx.appcompat.app.AppCompatActivity;
import android.text.TextUtils;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
import com.debatewithus.MainActivity;
import com.debatewithus.R;
import com.debatewithus.User;
import com.debatewithus.UserLocalStore;
import com.google.android.gms.tasks.OnCompleteListener;
import com.google.android.gms.tasks.Task;
import com.google.firebase.auth.AuthResult;
import com.google.firebase.auth.FirebaseAuth;
import static android.icu.lang.UCharacter.GraphemeClusterBreak.V;
public class LoginActivity extends AppCompatActivity {
protected void onCreate(Bundle savedInstanceState, ClassNotFoundException task) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_sign_up);
Button login;
Button sign_up;
final EditText mail;
final EditText mpassword;
TextView forgotpassword;
final FirebaseAuth auth;
auth = FirebaseAuth.getInstance();
mail = findViewById(R.id.username);
mpassword = findViewById(R.id.Password);
login = findViewById(R.id.login);
sign_up = findViewById(R.id.signup);
forgotpassword = findViewById(R.id.forgotpassword);
login.setOnClickListener((new View.OnClickListener() {
@Override
public void onClick(View v) {
finish();
}
}));
sign_up.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String email_address = mail.getText().toString().trim();
String password = mpassword.getText().toString().trim();
if (TextUtils.isEmpty(email_address)) {
mail.setError("Email is Required.");
return;
}
if (TextUtils.isEmpty(password)) {
mpassword.setError("Password Required.");
return;
if (!(password.length() < 8 && (password.length() > 15))) {
final EditText mpassword.mpassword.setError("Password Must be Between 8 and 15 Characters.");
return;
}
auth.signInWithEmailAndPassword(email_address, password).addOnCompleteListener(new OnCompleteListener<AuthResult>() {
@Override
public void onComplete(@NonNull Task<AuthResult> task) {
if (task.isSuccessful())
startActivity(new Intent(getApplicationContext(), MainActivity.class) {
});
else {
Toast.makeText(LoginActivity.this, "Error!" + task.getException().getMessage(), Toast.LENGTH_SHORT).show();
startActivity(new Intent(getApplicationContext(), MainActivity.class));
}
};
});
};
};
});
};
};
您需要與||
進行邏輯或而不是邏輯與&&
:
if (!(password.length() < 8 || (password.length() > 15)))
如果密碼長度小於 8 或大於 15,這將評估為真。
將 AND 替換為 OR,然后刪除。 . 應該這樣做。
如果 ((密碼.長度() < 8 || (密碼.長度() > 15))) {
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