從javascript中的對象數組中提取匹配值

Question

我有一個對象數組，我正在嘗試創建一個過濾器，其中用戶鍵入幾個字母並獲取所有匹配記錄的列表。

users = [{office: "J Limited", contact: {first_name: "James", last_name: "Wilson", address: Canada}},{office: "Q Limited", contact: {first_name: "Quin", last_name: "Ross", address: Australia}},{office: "N Limited", contact: {first_name: "Nancy", last_name: "Mathew"}, address: "England"}]

我有一個文本字段，用戶在其中鍵入以獲取結果，並假設用戶鍵入ja，因此結果應該搜索字段 office、contact first_name 和 last_name，如果任何此類字段包含匹配的字母，則應該是請求，在這種情況下，結果輸出應該是

J Limited, James, Wilson

請幫助我實現這一目標。

Answer 1

要獲得匹配的用戶，您可以執行以下操作：

const searchString = 'ja'

const matchingUsers = users.filter(user => 
  user.office.contains(searchString) || 
  user.contact.first_name.contains(searchString) || 
  user.contact.last_name.contains(searchString)
)

然后您可以隨意格式化匹配用戶列表

編輯： contains可能無法在一些JS版本的工作（在Chrome作品），所以更換contains有includes ：

const searchString = 'ja'

const matchingUsers = users.filter(user => 
  user.office.includes(searchString) || 
  user.contact.first_name.includes(searchString) || 
  user.contact.last_name.includes(searchString)
)

Answer 2

let users = [{
    office: "J Limited",
    contact: { first_name: "James", last_name: "Wilson", address: "Canada" }
}, {
    office: "Q Limited",
    contact: { first_name: "Quin", last_name: "Ross", address: "Australia" }
}, {
    office: "N Limited",
    contact: { first_name: "Nancy", last_name: "Mathew", address: "England"},
}];


// ig: i for case-insensitive, g for global
const regEx = new RegExp('ja', 'ig');

const result = users.filter(
    each =>
        each.office.match(regEx) ||
        each.contact.first_name.match(regEx) ||
        each.contact.last_name.match(regEx)
)
.map(
    each => [
        each.office,
        each.contact.first_name,
        each.contact.last_name
    ]
);

console.log(result);

Answer 3

您可以遍歷數組並搜索對象。

 users = [{ office: "J Limited", contact: { first_name: "James", last_name: "Wilson", address: "Canada" } }, { office: "Q Limited", contact: { first_name: "Quin", last_name: "Ross", address: "Australia" } }, { office: "N Limited", contact: { first_name: "Nancy", last_name: "Mathew" }, address: "England" }, { office: "J Limited", contact: { first_name: "Jacob", last_name: "Wilson", address: "Canada" } } ] function search(searchKey) { searchKey = searchKey.toLowerCase(); results = []; for (var i = 0; i < users.length; i++) { if (users[i].contact.first_name.toLowerCase().includes(searchKey) || users[i].contact.last_name.toLowerCase().includes(searchKey) || users[i].office.toLowerCase().includes(searchKey)) { results.push(users[i]); } } return results; } var resultObject = search("ja"); if (resultObject) { for(i in resultObject){ console.log(resultObject[i].office, resultObject[i].contact.first_name, resultObject[i].contact.last_name) } }

Answer 4

const filterUser = users.filter(user =>{ return user.office.toLowerCase().includes((searchField).toLowerCase()) });

您的 searchField 是 input 的值，現在可以使用 filteruser ，因為它將返回搜索中包含 office 名稱的用戶，或者如果 searchField 中未輸入任何內容則返回 all 。

您現在可以通過 filterUser 進行映射，以便能夠使用包含作為您的搜索字段的輸入值的用戶。