Python - 從嵌套字典訪問特定項目

Question

考慮以下嵌套字典：

{year: {region: {country: ((val1, val2), (val3, val4))}}}

{2015: {'Europe': {'Switzerland': ((1.0, 7.6), (0.419, 2.318))},
                  {'Iceland': ((1.2, 3.2), (2.3, 1.00))}}

我需要編寫一個函數，該函數將輸入國家名稱字符串和這個嵌套字典，並根據所述國家名稱打印/返回值。

我的主要問題是如何根據國家/地區名稱訪問這些數據？ 我需要使用嵌套的 for 循環嗎？ 就像是-

def search_country(country, nestedD):
    yr = nestedD.keys[0]
    for year in nestedD:
        region = nestedD[region]
        for region in year:
            country = nestedD[country]

根據指定的任何國家/地區，我需要能夠打印如下內容：

Year: 2015
Country: Ireland
Rank: 18
Score: 6.94
Family: 1.37
Health: 0.90
Freedom: 0.62

Answer 1

for year in nestedDict:
    for region in nestedDict[year]:
        if country in nestedDict[year][region]:
            print(f'{year} {country} val1:', nestedDict[year][region][country][0][0])
            print(f'{year} {country} val2:', nestedDict[year][region][country][0][1])
            print(f'{year} {country} val3:', nestedDict[year][region][country][1][0])
            print(f'{year} {country} val4:', nestedDict[year][region][country][1][1])

Answer 2

我不會推薦嵌套字典，但如果你真的想要，你可以這樣做：

d = {2015: {'Europe': {
    'Switzerland': {((1.0, 7.6), (0.419, 2.318))},
    'Iceland': {((1.2, 3.2), (2.3, 1.00))}
       }
       }
    }
                  
                  
                  
def search_country(selectedCountry, nestedD):
    for year,valueYear in d.items():
        for continent,countries in valueYear.items():
            for country, values in countries.items():
                if (country == selectedCountry):
                    print("Year: ",year,
                    "\nCountry: ", selectedCountry,
                    "\nRank: ", "--",
                    "\nScore: ", list(*values)[0][0],
                    "\nFamily: ", list(*values)[0][1],
                    "\nHealth: ", list(*values)[1][0],
                    "\nFreedom: ",list(*values)[1][1])
            
search_country('Switzerland', d)

輸出

Year:  2015 
Country:  Switzerland 
Rank:  -- 
Score:  1.0 
Family:  7.6 
Health:  0.419 
Freedom:  2.318

我真的找不到排名，但我希望這對你有幫助

Answer 3

看起來有點不必要的復雜，但如果你別無選擇，那么你可以使用它。

data = {
    2015: {
        'Europe':{
            'Switzerland': (
                (1.0, 7.6),
                (0.419, 2.318)
            ),

            'Iceland': (
                (1.2, 3.2),
                (2.3, 1.00)
            )
        }
    }
}

def get_data(country: str):
    for year, regions in data.items():
        for region, countries in regions.items():
            if country in countries.keys():
                stats = countries[country]

                print(
                    "Year: {0}\nCountry: {1}\nRank: {2}\nScore: {3}\nFamily: {4}\nHealth: {5}\nFreedom: {6}\n\n"\
                    .format(year, country, None, stats[0][0], stats[0][1], stats[1][0], stats[1][1])
                )

get_data("Iceland")