[英]Adding column to a dataframe in R based on matching conditions in another dataframe
我有 2 個數據框,我想向其中添加一列,並根據匹配條件從另一個數據框中添加值。 然后我想對許多大型數據集重復這一點。
# Example dataframe
DF1 <- data.frame(Batch = c('a', 'a', 'a', 'a', 'a', 'a', 'b', 'b', 'b', 'b', 'b', 'b'),
Patch1 = c(1, 1, 2, 2, 3, 3, 1, 1, 2, 2, 3, 3),
Patch2 = c(2, 3, 1, 3, 1, 2, 2, 3, 1, 3, 1, 2))
DF2 <- data.frame(Batch = c('a', 'a', 'a', 'b', 'b', 'b'),
Patch = c(1, 2, 3, 1, 2, 3),
Pop_size = sample(1:300, size=6, replace=TRUE))
對於 DF1,我想添加 2 列(Patch1_popsize 和 Patch2_popsize),其中 Pop_size 在 DF2 中給出,並帶有給定批次的相應補丁號
嘗試以這種方式使用match()
:
#Code
DF1$Patch1_Pop_size <- DF2[match(paste(DF1$Batch,DF1$Patch1),paste(DF2$Batch,DF2$Patch)),"Pop_size"]
DF1$Patch2_Pop_size <- DF2[match(paste(DF1$Batch,DF1$Patch2),paste(DF2$Batch,DF2$Patch)),"Pop_size"]
輸出:
DF1
Batch Patch1 Patch2 Patch1_Pop_size Patch2_Pop_size
1 a 1 2 137 254
2 a 1 3 137 211
3 a 2 1 254 137
4 a 2 3 254 211
5 a 3 1 211 137
6 a 3 2 211 254
7 b 1 2 78 81
8 b 1 3 78 43
9 b 2 1 81 78
10 b 2 3 81 43
11 b 3 1 43 78
12 b 3 2 43 81
嘗試這個:
DF3 <- merge(DF1,DF2, by.x = c("Batch","Patch1"), by.y=c("Batch","Patch"), all.x=TRUE) %>%
rename(Pop_size1=Pop_size)
DF3 <- merge(DF3,DF2, by.x = c("Batch","Patch2"), by.y=c("Batch","Patch"), all.x=TRUE) %>%
rename(Pop_size2=Pop_size)
我們可以使用data.table
方法,這會更快更有效
library(data.table)
setDT(DF1)[DF2, Patch1_Pop_size := Pop_size,
on = .(Batch, Patch1 = Patch)][DF2,
Patch2_Pop_size := Pop_size, on = .(Batch, Patch2 = Patch)]
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.