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Python append 二維 numpy 數組到 3D

[英]Python append 2D numpy array to 3D

我遇到了 numpy arrays 的理解問題。我有一個數據集,閱讀時看起來像這樣:

[
   [ F0, F1, F2, F3 ... F22],
   [ G0, G1, G2, G3 ... G22],
   [ H0, H1, H2, H3 ... H22],
   [ I0, I1, I2, I3 ... I22],
   [ J0, J1, J2, J3 ... J22]
]

我想將它們轉換為“三個一組”:

[
   [
      [ F0, F1, F2, F3 ... F22],
      [ G0, G1, G2, G3 ... G22],
      [ H0, H1, H2, H3 ... H22]
   ],
   [
      [ G0, G1, G2, G3 ... G22],
      [ H0, H1, H2, H3 ... H22],
      [ I0, I1, I2, I3 ... I22]
   ]
   ...
]

到目前為止,我已經寫了這段代碼:

data = loadtxt('./training_data/set_0.csv', delimiter=';')
batch_size=3
features=17
labels=6

trainX = np.empty((0,batch_size, features), float)
for i in range(0, len(data)-batch_size):
    row_X = data[i:i+batch_size,0:features]
    trainX = np.append(trainX, row_X)

print(trainX[0])

記錄 row_X 的形狀可以得到我想要的(3,17) 但是trainX變量似乎包含那些 arrays 的平面組合,我本trainX[0]的形狀是(batch_size,features)

import numpy as np

batch_size = 3


l = np.array([
   [1,2,3,4,5],
   [ 2,3,4,5,6],
   [ 3,4,5,6,7],
   [ 4,5,6,7,8],
   [ 5,6,7,8,9],
    [6,7,8,9,0],
])

output = [l[n:n+batch_size] for n in range(len(l)-batch_size+1)]

Output

[array([[1, 2, 3, 4, 5],
        [2, 3, 4, 5, 6],
        [3, 4, 5, 6, 7]]),
 array([[2, 3, 4, 5, 6],
        [3, 4, 5, 6, 7],
        [4, 5, 6, 7, 8]]),
 array([[3, 4, 5, 6, 7],
        [4, 5, 6, 7, 8],
        [5, 6, 7, 8, 9]]),
 array([[4, 5, 6, 7, 8],
        [5, 6, 7, 8, 9],
        [6, 7, 8, 9, 0]])]

假設您有一個二維 numpy 數組,如下所示:

arr = array([[7, 9, 4, 1, 0],
             [9, 5, 1, 8, 5],
             [6, 1, 9, 7, 1],
             [2, 8, 4, 8, 7],
             [1, 2, 6, 1, 8],
             [0, 2, 7, 0, 2]])

為了將其轉換為三維數組,您可以使用reshape function:

arr.reshape(3, 2, -1)

這給你三個“批次”,每批兩行。

array([[[7, 9, 4, 1, 0],
        [9, 5, 1, 8, 5]],

       [[6, 1, 9, 7, 1],
        [2, 8, 4, 8, 7]],

       [[1, 2, 6, 1, 8],
        [0, 2, 7, 0, 2]]])

最后一個參數-1告訴reshape ,在給定數組中元素的實際數量和其他維度的大小的情況下,計算第三維的大小。

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