[英]Post data to the WebApi which its parameter is not complex object using Httpclient
這是我的 webapi 發布請求
[HttpPost]
[Route("Create/{id}")]
public async Task<IActionResult> CreateContact(Guid id, string email, string fullName)
{
// code removed for brevity
}
如何將contact
object 發布到 webapi? 這就是我在客戶端中所擁有的。
using (var client = new HttpClient())
{
client.BaseAddress = new Uri("https://localhost:123");
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var contact = new Contact() { Id = 12345, Email = "test@gmail.com", FullName = "John" };
HttpResponseMessage response = await client.PostAsJsonAsync($"/api/Contact/Create/{contact.Id}", contact);
if (response.IsSuccessStatusCode)
{
}
else
{
}
}
不確定這是否是最好的,但它有效。 在Route
屬性中添加更多參數
[HttpPost]
[Route("Create/{id}/{email}/{fullName}")]
public async Task<IActionResult> CreateContact(Guid id, string email, string fullName)
{
// code removed for brevity
}
然后在 httpclient
HttpResponseMessage response = await client.PostAsJsonAsync($"/api/Contact/Create/{contact.Id}/{contact.Email}/{contact.FullName}", contact);
您好在您的 WPI 中使用 [FromBody]。 您可以將聯系人發布為 object
[HttpPost]
[Route("Create/{contact}")]
public async Task<IActionResult> CreateContact([FromBody]Contact contact)
{
// code removed for brevity
}
using (var client = new HttpClient())
{
client.BaseAddress = new Uri("https://localhost:123");
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var contact = new Contact() { Id = 12345, Email = "test@gmail.com", FullName = "John" };
var contactJson = JsonConvert.SerializeObject(contact);
var stringContent = new StringContent(contactJson , UnicodeEncoding.UTF8, "application/json");
HttpResponseMessage response = await client.PostAsync($"/api/Contact/Create/", stringContent);
if (response.IsSuccessStatusCode)
{
}
else
{
}
}
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