在 gsub r 中使用正則表達式模式

Question

您好，我有一個 df，例如

COL1         
BLOC1.1_3_10-355(+)Sp_3
BLOC2.1_10-355(-)SSp_4
BLOC3.1_10-355(+)SP_32
BLOC1_3_10-355(+)SP4_2

如何找到可以替換_ here > _[Number]-[Number](的正則表達式

:[Number]-[Number]( 

在這里我應該得到

COL1         
BLOC1.1_3:10-355(+)Sp_3
BLOC2.1:10-355(-)SSp_4
BLOC3.1:10-355(+)SP_32
BLOC1_3:10-355(+)SP4_2

我試過： gsub("_[0-9]-[0-9](",":[0-9]-[0-9](",df$COL1)

Answer 1

COL1 <- c("BLOC1.1_3_10-355(+)Sp_3",
"BLOC2.1_10-355(-)SSp_4",
"BLOC3.1_10-355(+)SP_32",
"BLOC1_3_10-355(+)SP4_2")

gsub( "(.*[0-9]+)(_)([0-9]+-.*)", "\\1:\\3", COL1)

[1] "BLOC1.1_3:10-355(+)Sp_3" "BLOC2.1:10-355(-)SSp_4"  "BLOC3.1:10-355(+)SP_32" 
[4] "BLOC1_3:10-355(+)SP4_2" 

Answer 2

您可以使用

_([0-9]+-[0-9]+\()

並替換為:並捕獲組 1。

正則表達式演示

COL1 <- c("BLOC1.1_3_10-355(+)Sp_3", "BLOC2.1_10-355(-)SSp_4", "BLOC3.1_10-355(+)SP_32", "BLOC1_3_10-355(+)SP4_2")
gsub("_([0-9]+-[0-9]+\\()", ":\\1", COL1)

Output

[1] "BLOC1.1_3:10-355(+)Sp_3" "BLOC2.1:10-355(-)SSp_4" 
[3] "BLOC3.1:10-355(+)SP_32"  "BLOC1_3:10-355(+)SP4_2"

Answer 3

使用字符串拆分的解決方案：

output <- sapply(COL1, function(x) {
    parts <- strsplit(x, "_(?=\\d+-)", perl=TRUE)
    paste(parts[[1]][1], parts[[1]][2], sep=":")
})
names(output) <- c(1:4)
output

                        1                         2                         3 
"BLOC1.1_3:10-355(+)Sp_3"  "BLOC2.1:10-355(-)SSp_4"  "BLOC3.1:10-355(+)SP_32" 
                        4 
 "BLOC1_3:10-355(+)SP4_2"

數據：

COL1 <- c("BLOC1.1_3_10-355(+)Sp_3", "BLOC2.1_10-355(-)SSp_4",
          "BLOC3.1_10-355(+)SP_32",  "BLOC1_3_10-355(+)SP4_2")