[英]Using regex pattern in gsub r
您好,我有一个 df,例如
COL1
BLOC1.1_3_10-355(+)Sp_3
BLOC2.1_10-355(-)SSp_4
BLOC3.1_10-355(+)SP_32
BLOC1_3_10-355(+)SP4_2
如何找到可以替换_
here > _[Number]-[Number](
的正则表达式
:[Number]-[Number](
在这里我应该得到
COL1
BLOC1.1_3:10-355(+)Sp_3
BLOC2.1:10-355(-)SSp_4
BLOC3.1:10-355(+)SP_32
BLOC1_3:10-355(+)SP4_2
我试过: gsub("_[0-9]-[0-9](",":[0-9]-[0-9](",df$COL1)
COL1 <- c("BLOC1.1_3_10-355(+)Sp_3",
"BLOC2.1_10-355(-)SSp_4",
"BLOC3.1_10-355(+)SP_32",
"BLOC1_3_10-355(+)SP4_2")
gsub( "(.*[0-9]+)(_)([0-9]+-.*)", "\\1:\\3", COL1)
[1] "BLOC1.1_3:10-355(+)Sp_3" "BLOC2.1:10-355(-)SSp_4" "BLOC3.1:10-355(+)SP_32"
[4] "BLOC1_3:10-355(+)SP4_2"
您可以使用
_([0-9]+-[0-9]+\()
并替换为:
并捕获组 1。
COL1 <- c("BLOC1.1_3_10-355(+)Sp_3", "BLOC2.1_10-355(-)SSp_4", "BLOC3.1_10-355(+)SP_32", "BLOC1_3_10-355(+)SP4_2")
gsub("_([0-9]+-[0-9]+\\()", ":\\1", COL1)
Output
[1] "BLOC1.1_3:10-355(+)Sp_3" "BLOC2.1:10-355(-)SSp_4"
[3] "BLOC3.1:10-355(+)SP_32" "BLOC1_3:10-355(+)SP4_2"
使用字符串拆分的解决方案:
output <- sapply(COL1, function(x) {
parts <- strsplit(x, "_(?=\\d+-)", perl=TRUE)
paste(parts[[1]][1], parts[[1]][2], sep=":")
})
names(output) <- c(1:4)
output
1 2 3
"BLOC1.1_3:10-355(+)Sp_3" "BLOC2.1:10-355(-)SSp_4" "BLOC3.1:10-355(+)SP_32"
4
"BLOC1_3:10-355(+)SP4_2"
数据:
COL1 <- c("BLOC1.1_3_10-355(+)Sp_3", "BLOC2.1_10-355(-)SSp_4",
"BLOC3.1_10-355(+)SP_32", "BLOC1_3_10-355(+)SP4_2")
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