如何在 C 中調用 Rust function？

Question

發布此消息時向我顯示的第一個“類似問題”稱為“如何在 Rust 中調用 C function”。 這與我需要的相反。 Every tutorial I can find that technically does answer my question, only does so by exporting the Rust function in a DLL so a C executable can call it, using extern "C" .

But I have a Rust executable that is calling a C DLL function that takes a Rust function pointer as a parameter (I haven't actually written this C function yet). 任何基本示例演示如何執行此操作？ I've already got Rust calling some of the C DLL functions, but I need to write code for both Rust and C so that C can execute a Rust callback.

Answer 1

If you have this C code compiled to a library named lib.dll , exporting a single function which accepts a pointer to a function which takes no arguments and returns nothing:

__declspec(dllexport) void foo(void (*callback)()) {
    callback();
}

然后這個 Rust 代碼會將 function callback發送到 C ZC1C425268E48385F14ZA70。 執行后，它會打印"callback()"行：

extern "C" fn callback() -> () {
    println!("callback()");
}

fn main() {
    println!("main()");
    call_dynamic();
}

fn call_dynamic() -> Result<u32, Box<dyn std::error::Error>> {
    unsafe {
        let lib = libloading::Library::new("lib.dll")?;
        let foo: libloading::Symbol<extern "C" fn(extern "C" fn()) -> u32> = lib.get(b"foo")?;
        Ok(foo(callback))
    }
}

您應該在控制台中看到：

main()
callback()

我在 Windows 上，並使用以下命令編譯了 C 代碼：

gcc --shared lib.c -o lib.dll

Rust 代碼運行如下：

cargo run