[英]create a list of dates with a while loop python
我想創建一個從 2020 年 10 月 9 日開始的日期列表,增量為 182 天,直到 2020 年 5 月 3 日。
我的代碼是這樣的:
start_date="10/09/2020"
last_date="05/03/2020"
start_date=datetimedatetime.strptime(date,"%d/%m/%Y").date()
last_date=datetimedatetime.strptime(date,"%d/%m/%Y").date()
dates=[]
while dates[-1] != last_date:
i=star_date+timedelta(days=182)
dates.append(i)
dates[i]=i+timedelta(days=pago_cupon)
我不知道你有什么問題。 你可以試試這段代碼
from datetime import date, timedelta
start_day = date(year=2020, month=9, day=10)
end_day = date(year=2021, month=3, day=5)
one_data_delta = timedelta(days=1)
res = []
while end_day != start_day:
start_day += one_data_delta
res.append(start_day)
print(res)
幾個問題:
star_date
而不是start_date
中有拼寫錯誤。!=
更改為小於等於或大於等於。(last_date - timedelta(days=182))
,這樣我們就不會超過 last_date。from datetime import datetime, timedelta
start="10/09/2020"
last="05/03/2022"
start_date=datetime.strptime(start,"%d/%m/%Y")
last_date=datetime.strptime(last,"%d/%m/%Y")
dates=[]
while start_date <= (last_date - timedelta(days=182)):
start_date += timedelta(days=182)
dates.append(start_date.strftime("%d/%m/%Y"))
# not quite sure what you are trying to do here:
#dates[i]=i+timedelta(days=pago_cupon)
print(dates)
Output:
['11/03/2021', '09/09/2021']
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