2 個列表的所有可能排列

Question

如果我有 2 個列表：

keys= ["key1", "key2", "key3", "key4", "key5", "key6", "key7", "key8",
         "key9", "key10", "key11", "key12", "key13", "key14", "key15", "key16"]

values= ["val1", "val2", "val3"]

# permutations = [list(zip(x, values)) for x in itertools.permutations(keys, len(values))]

我想得到 output 所有可能的排列（是 16^3 = 4096？），格式如下：

其中 [?,?,?] 表示所有排列值中的一組可能選項。

如何在 python 中實現這一點？

Answer 1

首先，我們將創建 256 個["val1", "val2", "val3", "val4"]的置換cases ，如4x4x4x4 = 256並且我們創建每個索引值的permutations列表，我們將在cases shuffling后添加

import itertools
import pandas as pd
import random
import numpy as np

coln = [f'Col{i}' for i in range(1, 257)]
values= ["val1", "val2", "val3", "val4"]
cases = [p for p in itertools.product(values, repeat= 4)]
keys= ["key1", "key2", "key3", "key4", "key5", "key6", "key7", "key8",
         "key9", "key10", "key11", "key12", "key13", "key14", "key15", "key16"]

permutations = []
for _ in range(16):
    random.shuffle(cases)
    permutations.append(cases)

df = pd.DataFrame(data = permutations, index= keys, columns= coln, dtype= np.object)
print(df)

輸出：