If I have 2 lists:
keys= ["key1", "key2", "key3", "key4", "key5", "key6", "key7", "key8",
"key9", "key10", "key11", "key12", "key13", "key14", "key15", "key16"]
values= ["val1", "val2", "val3"]
# permutations = [list(zip(x, values)) for x in itertools.permutations(keys, len(values))]
I want to get as output all possible permutations (is it 16^3 = 4096?) in such format:
where [?,?,?] represents a set of possible options within all permutations values.
How can I achieve that in python?
First we are going to create 256 permutation cases
of ["val1", "val2", "val3", "val4"]
as 4x4x4x4 = 256
and we create permutations
list whose each index value, we will add after shuffling
of cases
import itertools
import pandas as pd
import random
import numpy as np
coln = [f'Col{i}' for i in range(1, 257)]
values= ["val1", "val2", "val3", "val4"]
cases = [p for p in itertools.product(values, repeat= 4)]
keys= ["key1", "key2", "key3", "key4", "key5", "key6", "key7", "key8",
"key9", "key10", "key11", "key12", "key13", "key14", "key15", "key16"]
permutations = []
for _ in range(16):
random.shuffle(cases)
permutations.append(cases)
df = pd.DataFrame(data = permutations, index= keys, columns= coln, dtype= np.object)
print(df)
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