根據值列表過濾對象數組

Question

我有一個數組如下

array = [
{
  name: 'A'
  instructors: [
   {
     name:'InsA'
   }
  ]
  businessUnit: {name:'myBusiness'}
},
{
  name: 'B'
  instructors: [
   {
     name:'InsB'
   }
  ]
  businessUnit: {name:'myBusinessB'}
}

]

我想用我擁有的值過濾這個數組，這些值也在一個數組中，如下所示

nameArr = [A,C,D]
instructorArr = [InsA,InsC,InsZ]
businessName = [myBusinessB,myBusinessX,myBusinessD]

如果我只需要檢查一個值，是否可以過濾此數組，如下所示

const filtered = _.filter(groupActivityList, (obj) => {
      return (
        obj.name === (groupClassFilter !== defaultFilter ? groupClassFilter : obj.name) &&
        obj.instructors.length > 0 &&
        obj.instructors[0]?.name ===
          (groupInstructorFilter !== defaultFilter
            ? groupInstructorFilter
            : obj.instructors.length > 0 && obj.instructors[0]?.name) &&
        obj.businessUnit.name ===
          (groupFacilityFilter !== defaultFilter ? groupFacilityFilter : obj.businessUnit.name)
      );
    });

當我有一組值要過濾時，我如何過濾 Ex： nameArr = [A,C,D]

Answer 1

使用Array.prototype.some和Array.prototype.includes過濾數組的示例：

 const array = [{ name: 'A', instructors: [{ name: 'InsA' }], businessUnit: { name: 'myBusinessA' } }, { name: 'B', instructors: [{ name: 'InsB' }], businessUnit: { name: 'myBusinessB' } }, { name: 'Z', instructors: [{ name: 'InsZZ' }], businessUnit: { name: 'myBusinessZZ' } } ]; const nameArr = ['A', 'C', 'D'] const instructorArr = ['InsA', 'InsC', 'InsZ'] const businessName = ['myBusinessB', 'myBusinessX', 'myBusinessD', 'myBusinessA'] const filtered = array.filter(el => nameArr.includes(el.name) && el.instructors.some(ins => instructorArr.some(iA => ins.name === iA)) && businessName.includes(el.businessUnit.name) ); console.log(filtered);

Answer 2

如果我正確理解問題，您可以使用Array#some屬性。

代替檢查obj.name === filterObj.name ，您可以使用fiterObj.names.some(name => name === obj.name)進行檢查，如果namesArr中的任何元素與對象的名稱匹配，它將返回 true