Xml 來自 URL 的請求和響應

Question

我正在嘗試從 URL 獲得響應，該響應采用 Xml 輸入並返回 Xml Z78E66221F63983D1CE31

And there is this case when this Url returns Bad Request 400, in this case in code I'll get an exception and I can't view the Xml, but if I tried the same input in postman I'll get the Xml output.

In case of the exception I can catch this exception by using WebException , but here in the end when I read the response using reader.ReadToEnd() I'll get a JSON not the Xml output that I got from postman

Postman output 示例：

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<RESPONSE MODE="DIRECT" TYPE="PINPRINTING">
    <RESULTMESSAGE>User not allowed to process</RESULTMESSAGE>
</RESPONSE>

這是我的代碼：

public void GetResponse()
        {
            try
            {
                HttpWebRequest request = (HttpWebRequest)WebRequest.Create(myURL);
                request.Accept = "application/xml";

                byte[] requestInFormOfBytes = System.Text.Encoding.ASCII.GetBytes(requestXmlDoc.InnerXml);
                request.Method = "POST";
                request.ContentType = "text/xml;charset=utf-8";
                request.ContentLength = requestInFormOfBytes.Length;
                Stream requestStream = request.GetRequestStream();

                requestStream.Write(requestInFormOfBytes, 0, requestInFormOfBytes.Length);
                requestStream.Close();

                HttpWebResponse response = (HttpWebResponse)request.GetResponse();
                StreamReader respStream = new StreamReader(response.GetResponseStream(), System.Text.Encoding.Default);
                string receivedResponse = respStream.ReadToEnd();
            }
            catch (WebException e)
            {
                using (WebResponse response = e.Response)
                {
                    HttpWebResponse httpResponse = (HttpWebResponse)response;
                    Console.WriteLine("Error code: {0}", httpResponse.StatusCode);
                    using (Stream data = response.GetResponseStream())
                    using (var reader = new StreamReader(data, ASCIIEncoding.ASCII))
                    {
                        string text = reader.ReadToEnd();

                        Console.WriteLine(text);
                    }
                }
            }
        }

返回的 JSON 是這樣的：

{
  "status": 400,
  "statusDesc": "Invalid input"
}

Answer 1

嘿，我找到了答案，它是內容類型。 更改：request.ContentType = "text/xml;charset=utf-8"; 到這個 request.ContentType = "application/xml"; 現在我得到了我需要的 Xml