在 MySQL 8 版本中使用替換和連接

Question

我在一列中有如下字符串值：

<span style=text-align: justify;>Lorem Ipsum is simply dummy text of the printing and typesetting industry.</span>

我想執行如下平衡字符串替換：

<p style=margin-top: 0;>Lorem Ipsum is simply dummy text of the printing and typesetting industry.</p>

我嘗試使用 REPLACE 和 CONCAT 函數來執行此操作，但沒有得到所需的 output。

例如：

mysql> SELECT REPLACE (
        contents,
        CONCAT( "<span style=text-align: justify;>", contents, "</span>" ),
CONCAT( "<p style=margin-top: 0;>", contents, "</p>" )) q 
FROM
    t_contents 
WHERE
    contents LIKE '%<span style=text-align: justify;>%';

+--------------------------------------------------------------------------------------------------------------------+
| q                                                                                                                  |
+--------------------------------------------------------------------------------------------------------------------+
| <span style=text-align: justify;>Lorem Ipsum is simply dummy text of the printing and typesetting industry.</span> |
+--------------------------------------------------------------------------------------------------------------------+
1 row in set (0.14 sec)

如何在 MySQL 8 版本中實現此結果？

Answer 1

嘗試這樣的事情：

SELECT REPLACE( REPLACE(
'<span style=text-align: justify;>Lorem Ipsum is simply dummy text of the printing and typesetting industry.</span>','<span style=text-align: justify;>','<p style=margin-top: 0;>'),
'</span>','</p>')
;