[英]Format MySQL using CONCAT
多虧了一些幫助,我才有了一個從2014-10-10開始的MySQL查詢,並對12個月內的假期數量進行了罰款,例如2014-10-10至2015-10-09,然后2015-10-10至2016-10- 09
SELECT
e.name AS Employee,
CEIL(DATEDIFF(h.date, e.startdate)/365) as Year,
count(h.date) as Holidays_Taken
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year
結果
+----------+------+---------------+
| Employee | Year | Holidays_Taken|
+----------+------+---------------+
| Jon | 1 | 5 |
+----------+------+---------------+
| Jon | 2 | 1 |
+----------+------+---------------+
是否可以將2014年10月10日到2015年10月9日而不是從1年開始顯示,然后將2015年10月10日到2016年10月9日作為第二年顯示
這是我的SQL FIDDLE
謝謝
不確定我是否有您的目標,但這是我的方法:
http://sqlfiddle.com/#!9/371a7/14
SELECT
e.name AS Employee,
@year := CEIL(DATEDIFF(h.date, e.startdate)/365) AS Year,
CONCAT(DATE_ADD(e.startdate, INTERVAL @year-1 YEAR),' - ',DATE_ADD(e.startdate, INTERVAL @year YEAR)),
COUNT(h.date) AS Holidays_Taken,
SUM(h.hours) AS Hours
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year
我將以這種方式創建CONCAT
:
SELECT
e.name AS Employee,
CONCAT(
CEIL(DATEDIFF(h.date, e.startdate)/365),
' (',
DATE_ADD(e.startdate, INTERVAL FLOOR(DATEDIFF(h.date, e.startdate)/365) YEAR), ' to ',
DATE_ADD(e.startdate, INTERVAL CEIL(DATEDIFF(h.date, e.startdate)/365) YEAR),
')'
) as Year,
COUNT(h.date) AS Holidays_Taken,
SUM(h.hours) AS Hours
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year
演示: SQL FIDDLE
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