使用CONCAT格式化MySQL

Question

多亏了一些帮助，我才有了一个从2014-10-10开始的MySQL查询，并对12个月内的假期数量进行了罚款，例如2014-10-10至2015-10-09，然后2015-10-10至2016-10- 09

SELECT 
    e.name AS Employee,
    CEIL(DATEDIFF(h.date, e.startdate)/365) as Year,
    count(h.date) as Holidays_Taken
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year

结果

+----------+------+---------------+
| Employee | Year | Holidays_Taken|
+----------+------+---------------+
| Jon      | 1    | 5             |
+----------+------+---------------+
| Jon      | 2    | 1             |
+----------+------+---------------+

是否可以将2014年10月10日到2015年10月9日而不是从1年开始显示，然后将2015年10月10日到2016年10月9日作为第二年显示

这是我的SQL FIDDLE

谢谢

Answer 1

不确定我是否有您的目标，但这是我的方法：

http://sqlfiddle.com/#!9/371a7/14

SELECT 
    e.name AS Employee,
    @year := CEIL(DATEDIFF(h.date, e.startdate)/365) AS Year,
    CONCAT(DATE_ADD(e.startdate, INTERVAL @year-1 YEAR),' - ',DATE_ADD(e.startdate, INTERVAL @year YEAR)),
    COUNT(h.date) AS Holidays_Taken,
    SUM(h.hours) AS Hours
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1 
GROUP BY Year

Answer 2

我将以这种方式创建CONCAT ：

SELECT 
    e.name AS Employee,
    CONCAT(
        CEIL(DATEDIFF(h.date, e.startdate)/365), 
        ' (',
        DATE_ADD(e.startdate, INTERVAL FLOOR(DATEDIFF(h.date, e.startdate)/365) YEAR), ' to ',        
        DATE_ADD(e.startdate, INTERVAL CEIL(DATEDIFF(h.date, e.startdate)/365) YEAR),
        ')'
        ) as Year,
    COUNT(h.date) AS Holidays_Taken,
    SUM(h.hours) AS Hours
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year

演示： SQL FIDDLE