[英]Format MySQL using CONCAT
Thanks to some help I have a MySQL query that starts on 2014-10-10 and fines the amount of holidays in 12 months period eg 2014-10-10 to 2015-10-09 then 2015-10-10 to 2016-10-09 多亏了一些帮助,我才有了一个从2014-10-10开始的MySQL查询,并对12个月内的假期数量进行了罚款,例如2014-10-10至2015-10-09,然后2015-10-10至2016-10- 09
SELECT
e.name AS Employee,
CEIL(DATEDIFF(h.date, e.startdate)/365) as Year,
count(h.date) as Holidays_Taken
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year
With a result 结果
+----------+------+---------------+
| Employee | Year | Holidays_Taken|
+----------+------+---------------+
| Jon | 1 | 5 |
+----------+------+---------------+
| Jon | 2 | 1 |
+----------+------+---------------+
Is it possible to have the year show 2014-10-10 to 2015-10-09 instead of year 1 then 2015-10-10 to 2016-10-09 for year 2 是否可以将2014年10月10日到2015年10月9日而不是从1年开始显示,然后将2015年10月10日到2016年10月9日作为第二年显示
Here's my SQL FIDDLE 这是我的SQL FIDDLE
Thanks 谢谢
Not sure I've got your goal, but here is my approach: 不确定我是否有您的目标,但这是我的方法:
http://sqlfiddle.com/#!9/371a7/14 http://sqlfiddle.com/#!9/371a7/14
SELECT
e.name AS Employee,
@year := CEIL(DATEDIFF(h.date, e.startdate)/365) AS Year,
CONCAT(DATE_ADD(e.startdate, INTERVAL @year-1 YEAR),' - ',DATE_ADD(e.startdate, INTERVAL @year YEAR)),
COUNT(h.date) AS Holidays_Taken,
SUM(h.hours) AS Hours
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year
I would create the CONCAT
in this manner: 我将以这种方式创建
CONCAT
:
SELECT
e.name AS Employee,
CONCAT(
CEIL(DATEDIFF(h.date, e.startdate)/365),
' (',
DATE_ADD(e.startdate, INTERVAL FLOOR(DATEDIFF(h.date, e.startdate)/365) YEAR), ' to ',
DATE_ADD(e.startdate, INTERVAL CEIL(DATEDIFF(h.date, e.startdate)/365) YEAR),
')'
) as Year,
COUNT(h.date) AS Holidays_Taken,
SUM(h.hours) AS Hours
FROM employees AS e
LEFT JOIN holidays_taken AS h ON e.id = h.empid
WHERE e.id = 1
GROUP BY Year
DEMO: SQL FIDDLE 演示: SQL FIDDLE
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