[英]How to call Stored Procedure with Joins in Entity framework?
.Net 核心 3.1
這是我的桌子
我不允許在其中添加任何外鍵或新關系。 我制作了一個將其他 3 個表連接到 Ordering_Policy 表的存儲過程。
create procedure spOrderingPolicy
as
select op.Id, op.Tyre_Grade, op.Tyre_Group, tb.Tyre_Brand, ss.Status, tc.Cosmetic
from [dbo].[Ordering_Policy] as op
left join [dbo].[Tyre_Brand] as tb
on op.Tyre_Brand_Id = tb.Id
left join [dbo].[Shearography_Status] as ss
on op.Shearography_Id = ss.Id
left join [dbo].[Tyre_Cosmetic] as tc
on op.Cosmetic_Id = tc.Id
go
結果結果如預期:
所以我嘗試調用該程序:
public IEnumerable<OrderingPolicy> GetOrder()
{
using (Ordering_PolicyContext context = new Ordering_PolicyContext())
{
var order = context.OrderingPolicies.FromSqlRaw<OrderingPolicy>("spOrderingPolicy").ToList();
return order;
}
}
但它忽略了 Ordering_Policy 中沒有的任何內容:結果
如何調用該過程並顯示查詢中的所有數據?
編輯:這是用於 OrderingPolicy 的 class
namespace Ordering_Policy.Models
{
public partial class OrderingPolicy
{
public int Id { get; set; }
public string TyreGrade { get; set; }
public int? TyreGroup { get; set; }
public int? ShearographyId { get; set; }
public string CasingLife { get; set; }
public string Variance { get; set; }
public string ColorCode { get; set; }
public string Injury { get; set; }
public int? MaxCrownPatch { get; set; }
public int? MaxShoulder { get; set; }
public int? Age { get; set; }
public int? CosmeticId { get; set; }
public int? TyreBrandId { get; set; }
}
}
您需要創建一個與存儲過程返回的結果集匹配的無鍵實體類型,並在該 DbSet 而不是OrderingPolicy
OrderingPolicyEx.FromSqlRaw
您應該使用INNER Join而不是 left Join:
這是我的演示,帶有您的實體類(有點簡化):
CREATE PROCEDURE [dbo].[spOrderingPolicy]
as
select op.Id, op.TyreGrade,
op.TyreGroup,op.CosmeticId,op.ShearographyId,op.TyreBrandId, tb.Brand, ss.status,
tc.cosmetic
from dbo.OrderingPolicy as op
INNER JOIN [dbo].[Tyre_Brand] as tb
on op.TyreBrandId = tb.Id
INNER JOIN [dbo].[Shearography_Status] as ss
on op.ShearographyId = ss.Id
INNER JOIN [dbo].[Tyre_Cosmetic] as tc
on op.CosmeticId = tc.Id
Go
結果:只顯示匹配的行
我終於找到了解決方案:制作新的 class 和上下文,僅用於調用存儲過程中的列
Class:
public partial class Tyre_Detail
{
public int? Id { get; set; }
public string Tyre_Grade { get; set; }
public int? Tyre_Group { get; set; }
public string Tyre_Brand { get; set; }
public string Status { get; set; }
public string Cosmetic { get; set; }
}
數據必須具有與存儲過程中的列完全相同的名稱。 這個 class 中沒有鍵,所以數據類型,在這種情況下是int
需要有問號。
然后為 class 創建上下文文件:
modelBuilder.Entity<Tyre_Detail>(entity =>
{
entity.HasNoKey();
entity.Property(e => e.Id);
entity.Property(e => e.Tyre_Grade);
entity.Property(e => e.Tyre_Group);
entity.Property(e => e.Tyre_Brand);
entity.Property(e => e.Status);
entity.Property(e => e.Cosmetic);
});
由於這是無密鑰實體,因此 .HasNoKey() 是必不可少的。
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