[英]IRR calculation with Javascript
我有這段代碼來計算 IRR(內部收益率),它的工作原理類似於 Excel 中的 IRR function(我們有現金流值和猜測率)。
這工作正常,我的結果與 Excel function 相同,但是當 IRR 稅大於 100% 時,此 function 不起作用。 我得到的最大值是 100%。
我需要更改什么才能獲得大於 100 的值?
// Credits: algorithm inspired by Apache OpenOffice
// Calculates the resulting amount
var irrResult = function(values, dates, rate) {
var r = rate + 1;
var result = values[0];
for (var i = 1; i < values.length; i++) {
result += values[i] / Math.pow(r, (dates[i] - dates[0]) / 365);
}
return result;
}
// Calculates the first derivation
var irrResultDeriv = function(values, dates, rate) {
var r = rate + 1;
var result = 0;
for (var i = 1; i < values.length; i++) {
var frac = (dates[i] - dates[0]) / 365;
result -= frac * values[i] / Math.pow(r, frac + 1);
}
return result;
}
// Initialize dates and check that values contains at least one positive value and one negative value
var dates = [];
var positive = false;
var negative = false;
for (var i = 0; i < values.length; i++) {
dates[i] = (i === 0) ? 0 : dates[i - 1] + 365;
if (values[i] > 0) positive = true;
if (values[i] < 0) negative = true;
}
// Return error if values does not contain at least one positive value and one negative value
if (!positive || !negative) return 0;
// Initialize guess and resultRate
var guess = (typeof guess === 'undefined') ? 0.1 : guess;
var resultRate = guess;
// Set maximum epsilon for end of iteration
var epsMax = 1e-10;
// Set maximum number of iterations
var iterMax = 200;
// Implement Newton's method
var newRate, epsRate, resultValue;
var iteration = 0;
var contLoop = true;
do {
resultValue = irrResult(values, dates, resultRate);
newRate = resultRate - resultValue / irrResultDeriv(values, dates, resultRate);
epsRate = Math.abs(newRate - resultRate);
resultRate = newRate;
contLoop = (epsRate > epsMax) && (Math.abs(resultValue) > epsMax);
} while(contLoop && (++iteration < iterMax));
if(contLoop) return 0;
// Return internal rate of return
return resultRate;
}
var irrResult = function(values, dates, rate) {
var r = rate + 1;
var result = values[0];
for (var i = 1; i < values.length; i++) {
result += values[i]/ Math.pow(r, (dates[i] - dates[0]) );
}
return result / 365;
}
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