[英]R calculate distance in miles using 2 latitude & 2 longitude vectors in a data frame for 18k rows
我有一個包含 6 列的數據框:
- location id 1
- latitude 1
- longitude 1
- location id 2
- latitude 2
- longitude 2
我想計算兩個點之間的距離(以英里為單位)並將其添加為新列。 我正在努力尋找能夠做到這一點的 function。 我找到的最接近的是這里: https://blog.exploratory.io/calculating-distances-between-two-geo-coded-locations-358e65fcafae但它失敗了,因為它找不到名為'list_extract的list_extract
'。
以下是數據示例:
structure(list(df1_location_number = c(5051, 5051, 5051, 5051,
5051), df1_Latitude = c(34.7171375, 34.7171375, 34.7171375, 34.7171375,
34.7171375), df1_Longitude = c(-118.9107316, -118.9107316, -118.9107316,
-118.9107316, -118.9107316), df2_location_number = c(3051, 3085,
3022, 3041, 3104), df2_Latitude = c(34.7171375, 39.53404, 31.626788,
35.247982, 39.33425), df2_Longitude = c(-118.9107316, -93.292373,
-88.330116, -84.804119, -123.713064)), row.names = c(NA, 5L), class = "data.frame")
有什么建議么?
library(geodist)
是一個用於計算距離的好且快速的庫,並且geodist_vec()
function 被矢量化以處理數據的“列”
library(geodist)
## calcualte distance in metres using Haversine formula
df$dist_m <- geodist::geodist_vec(
x1 = df$df1_Longitude
, y1 = df$df1_Latitude
, x2 = df$df2_Longitude
, y2 = df$df2_Latitude
, paired = TRUE
, measure = "haversine"
)
## convert to miles
df$dist_miles <- df$dist_m / 1609
# df1_location_number df1_Latitude df1_Longitude df2_location_number df2_Latitude df2_Longitude dist_m dist_miles
# 1 5051 34.71714 -118.9107 3051 34.71714 -118.91073 0.0 0.0000
# 2 5051 34.71714 -118.9107 3085 39.53404 -93.29237 2327593.8 1446.6089
# 3 5051 34.71714 -118.9107 3022 31.62679 -88.33012 2859098.6 1776.9413
# 4 5051 34.71714 -118.9107 3041 35.24798 -84.80412 3095858.6 1924.0886
# 5 5051 34.71714 -118.9107 3104 39.33425 -123.71306 667849.7 415.0713
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